[英]Sorting 2d arrays using Java Comparator
I have a 2d array called interval[g][2] where g is some number. 我有一个称为interval [g] [2]的二维数组,其中g是一些数字。 Currently, I'm trying to sort the array first by increasing order in the first element, and if they are equal, sort by decreasing order in the second element.
目前,我正在尝试通过在第一个元素中按升序对数组进行排序,如果它们相等,则通过在第二个元素中按降序进行排序。
I've attempted this in two ways: 我尝试了两种方式:
1) Using Java 8's Comparator.comparing method : 1)使用Java 8的Comparator.comparing方法 :
Arrays.sort(interval, Comparator.comparing((int[] arr) -> arr[0]));
2) Using Arrays.sort : 2)使用Arrays.sort :
Arrays.sort(interval, new Comparator<int[]>() {
@Override
public int compare(int[] s1, int[] s2) {
if (s1[0] > s2[0])
return 1;
else if (s1[0] < s2[0])
return -1;
else {
if(s1[1] < s2[1])
return 1;
else if (s1[1] > s2[1])
return -1;
else
return 0;
}
}
});
The first method returns a partially sorted list. 第一种方法返回部分排序的列表。
[[0, 10], [10, 30], [30, 50]]
[[0, 10], [3, 19], [35, 45]]
[[10, 30], [27, 33], [30, 50]]
[[-10, 10], [0, 20], [35, 45]]
[[10, 30], [20, 40], [30, 50]]
[[0, 20], [8, 28], [37, 43]]
[[0, 20], [15, 35], [37, 43]]
[[0, 0], [8, 28], [10, 40]]
As you can see, it's sorting things in a set of three tuples. 如您所见,它以三个元组为一组对事物进行排序。
The second method doesn't sort the array at all. 第二种方法根本不对数组排序。 Can I not sort using primitive data types?
我不能使用原始数据类型进行排序吗? Can anyone advise?
有人可以建议吗?
I think you're looking for this: 我认为您正在寻找这个:
Arrays.sort(interval, Comparator.comparingInt((int[] arr) -> arr[0]).thenComparing(Comparator.comparingInt((int[] arr) -> arr[1]).reversed()));
Or if you want to go with the custom Comparator
: 或者,如果您想使用自定义
Comparator
:
Arrays.sort(interval, new Comparator<int[]>() {
@Override
public int compare(int[] o1, int[] o2) {
int result = Integer.compare(o1[0], o2[0]);
if (result == 0) {
result = Integer.compare(o2[1], o1[1]);
}
return result;
}
});
int[][] interval = new int[][] { {0, 10}, {10, 30}, {30, 50}, {0, 10}, {3, 19}, {35, 45}, {10, 30}, {27, 33}, {30, 50}, {-10, 10}, {0, 20}, {35, 45}, {10, 30}, {20, 40}, {30, 50}, {0, 20}, {8, 28}, {37, 43}, {0, 20}, {15, 35}, {37, 43}, {0, 0}, {8, 28}, {10, 40} };
Arrays.sort(interval, Comparator.<int[]>comparingInt(arr -> arr[0]).thenComparing(arr -> arr[1], Comparator.<Integer>naturalOrder().reversed()));
Stream.of(interval).forEachOrdered(ints -> System.out.println(Arrays.toString(ints)));
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