[英]Percentages of "categorical values" in one column based on subset of data frame R
I have data that consists of three columns (as an example) named data$engine, data$unit, and data$Turn.我的数据由名为 data$engine、data$unit 和 data$Turn 的三列(作为示例)组成。 data$Turn is categorical variable with values 0, 1 and 2. For each unique value of data$engine, there can be several values of data$unit.
data$Turn 是具有值 0、1 和 2 的分类变量。对于 data$engine 的每个唯一值,data$unit 可以有多个值。
I would like to calculate percent of 0, 1, and 2 in data$Turn for unique data$unit and data$engine respectively.我想分别为唯一的 data$unit 和 data$engine 计算 data$Turn 中 0、1 和 2 的百分比。 I have hundred thousand rows but I am pasting data structure for only two unique values of data$engine... Please note that that each data$unit (for specific data$engine) can have thousands of rows, and thus for calculating %ages, i would like to proceed as:
我有十万行,但我只为 data$engine 的两个唯一值粘贴数据结构...请注意,每个 data$unit(对于特定的 data$engine)可以有数千行,因此用于计算 %ages ,我想继续:
%age of 0's for data$unit 207 and data$engine 1111 =
counts of all zeros within data$unit 207 and data$engine 1111 (DIVIDED BY)
summation of all counts of 0, 1, and 2 for this data$unit and data$engine.*emphasized text*
Similarly for % ages of 1's and 2's for data$unit 207 and data$engine 1111,
and it continues for all other values of units and engines....
data$engine data$unit data$AvailableLeft
1111 207 1
1111 207 0
1111 207 2
1111 207 0
1111 207 0
1111 207 2
1111 207 0
1111 207 1
1111 208 0
1111 208 1
1111 208 2
1111 208 1
1122 209 2
1122 209 2
1122 209 0
1122 209 0
1122 209 1
I would like to get my output in this manner ie getting average %age of 0, 1, and 2s for each data$unit and for each data$engine:我想以这种方式获得我的输出,即为每个 data$unit 和每个 data$engine 获得 0、1 和 2s 的平均百分比:
data$engine data$unit %age of 0s %age of 1s %age of 2s
1111 207 ? ? ?
1111 208 ? ? ?
1122 209 ? ? ?
. . .
. . .
. . .
you can use data.table
:你可以使用
data.table
:
library(data.table)
setDT(data)[, .(p0=sum(AvailableLeft==0)/.N,
p1=sum(AvailableLeft==1)/.N,
p2=sum(AvailableLeft==2)/.N),
keyby=.(data, engine, unit)]
engine unit p0 p1 p2
1: 1111 207 0.50 0.25 0.25
2: 1111 208 0.25 0.50 0.25
3: 1122 209 0.40 0.20 0.40
library(data.table)
dt <- as.data.table(your_data)
dt[,.("p1"=paste(as.character(round(sum(data.AvailableLeft==1)*100/.N,2)),"%")),.(data.engine,data.unit)]
I would leave the %
of data.AvailableLeft==0
and %
of data.AvailableLeft==2
as figuring out them is trivial from here我会留下
%
of data.AvailableLeft==0
和%
of data.AvailableLeft==2
因为从这里找出它们是微不足道的
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