比较两个日期结果0

Question

so i'm currently making a small php application and I need to compare two dates to get the number of days between them. I sadly can't use datediff() since the php version is 5.2.

I've search how to do and I found a lot of answers but I always have the same problem. When I make the difference between my dates, I always got 0 as a result.

function date_diff($dateFrom, $dateTo) {
    echo $dateFrom->format('d-m-Y') . " : " . $dateTo->format('d-m-Y') . '<br/>';
    $diff = abs($dateTo-$dateFrom);

    return sprintf
    (
        "%d Days, %d Hours, %d Mins, %d Seconds",
        intval( $diff / 86400 ),
        intval( ( $diff % 86400 ) / 3600),
        intval( ( $diff / 60 ) % 60 ),
        intval( $diff % 60 )
    );
}

I currently use this function and the parameters are here :

    while ($donnees = mysqli_fetch_array($res))
        $date = new DateTime($donnees['Date']);


    $date = date_create($date->format("Y-m-d"));
    $today = new DateTime();

    echo $utilDate->date_diff($date, $today);

My $date and $today variables are not empty, so I don't understand why this code doesn't work. Does anyone have an idea?

Answer 1

I think $dateTo and $dateFrom are objects and you are doing a substraction on them in $diff = abs($dateTo-$dateFrom);

Try $diff = abs($dateTo->getTimestamp()-$dateFrom->getTimestamp());

Answer 2

You want to use the diff operator:

function date_diff($dateFrom, $dateTo) {
    echo $dateFrom->format('d-m-Y') . " : " . $dateTo->format('d-m-Y') . '<br/>';
    $diff = $dateNow->diff($dateTo);

    $day = $diff->format('%d');
    $hour = $diff->format('%h');
    $min = $diff->format('%i');
    $seconds = $diff->format('%s');

    return /*string involving above formats*/;
}