用bash将txt文件分块为html表

Question

I have a ~600 line .txt file, all.txt. I want to turn it into an HTML table with two columns where the first column contains the entire contents of all.txt with exactly five lines in each row (so the table would have about 120 rows total). Here's what I have so far:

#!/bin/bash
A=10
B=5
len=`wc -l < all.txt`
len2=$((len / 5))

while [ $A -le $len2 ]; do
    head -$A all.txt | tail -$B |
    awk '
    BEGIN{print " "} 
    {printf("<tr><td></td><td></td></tr>\n")}
    END{print " "}
    '
    let A+=5
done

As you can see, this is really just a shell of a script, and I'm not sure what to with awk inside the loop. Is using awk inside a control structure like this even the best way to do it? Is bash even a reasonable way to do it?

Answer 1

sed alternative

 $ sed -e '5~5a</td>\n<td></td>\n</tr>' -e '1~5i<tr>\n<td>' <(seq 15)

<tr>
<td>
1
2
3
4
5
</td>
<td></td>
</tr>
<tr>
<td>
6
7
8
9
10
</td>
<td></td>
</tr>
<tr>
<td>
11
12
13
14
15
</td>
<td></td>
</tr>

Answer 2

You properly only need awk:

awk 'NR%5 == 1{printf "%s<tr><td>", NR > 1 ? "</td><td></td></tr>" : ""}1' all.txt

Might need to add END{print "</td><td></td></tr>"} at the end.