RegExp 匹配任意字符串 + 8 位数字

Question

Trying to match urls in the format of arbitrary string + dash + 8 digits:

yellow-purse-65788544
big-yellow-purse-66784500
iphone-smart-case-water-resistant-55006610

I've built this this one, but it doesn't work:

new RegExp(/^[a-z][A-Z]-\d{8}$/).test('big-yellow-purse-66784500'); // false

Can you help me fix my broken RegExp?

Answer 1

The string is not completely arbitrary. It would be lowercase dashed alpha numeric.

You can use the following regex, which rules out a list of false positives that other answers do not account for (detailed in the Regex101):

^(?:[a-z0-9]+-)+\d{8}$

Regex101

Example construction:

 document.body.textContent = /^(?:[a-z0-9]+-)+\\d{8}$/.test('big-yellow-purse-66784500');

Answer 2

尝试这个：

/^([a-zA-Z]*-)+\d{8}$/.test("iphone-smart-case-water-resistant-55006610");

Answer 3

You string has several dashes ( - ) but the regex just have the last one , try this:

/^[a-z-]+-\d{8}$/im

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Regex101 Demo

https://regex101.com/r/rT7xT0/1

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Regex explanation:

/^[a-z-]+-\d{8}$/im

    ^ assert position at start of a line
    [a-z-]+ match a single character present in the list below
        Quantifier: + Between one and unlimited times, as many times as possible, giving back as needed [greedy]
        a-z a single character in the range between a and z (case insensitive)
        - the literal character -
    - matches the character - literally
    \d{8} match a digit [0-9]
        Quantifier: {8} Exactly 8 times
    $ assert position at end of a line
    i modifier: insensitive. Case insensitive match (ignores case of [a-zA-Z])
    m modifier: multi-line. Causes ^ and $ to match the begin/end of each line (not only begin/end of string)

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Demo:

 stringOne = "iphone-smart-case-water-resistant-55006610"; stringtwo = "big-yellow-purse-66784500"; stringThree = "iphone-smart-case-water-resistant-55006610222222"; var myregexp = /^[az-]+-\\d{8}$/im; if(myregexp.test(stringOne)){ document.write(stringOne + " - TRUE<br>"); }else{ document.write(stringOne + " - FALSE<br>"); } if(myregexp.test(stringtwo)){ document.write(stringtwo + " - TRUE<br>"); }else{ document.write(stringtwo + " - FALSE<br>"); } if(myregexp.test(stringThree)){ document.write(stringThree + " - TRUE<br>"); }else{ document.write(stringThree + " - FALSE<br>"); }

Answer 4

If the string really can be arbitrary, you can use this:

/^.*?-\d{8}$/i

The .+? is a non-greedy match for any characters, and \\d{8} says to match exactly 8 digits.

Alternatively, you could use:

/^[\w-]+?-\d{8}$/i

This matches any number of "word" or '-' characters, followed by a '-' and 8 digits.

These both also match the case commonly seen with human-readable URLs in which there are multiple '-' characters in sequence, which can happen by converting something like "Dollar $ign money clip" to "dollar--ign-money clip".