[英]how to return the multiple lists from controller action to ajax success call back function
I am creating a mvc .net project in which i have the jquery ajax request is as follows 我正在创建一个mvc .net项目,其中我有jquery ajax请求如下
$.ajax({
url: "@Url.Action("getdata", "SeatPlans")",
data: { seat_plane_id : 17},
type: "POST",
dataType: "json",
success: function (data) {
loadData(data);
},
error: function () {
alert("Failed! Please try again.");
}
});
which call the following controller action 它调用以下控制器动作
public JsonResult getdata(int seat_plane_id)
{
int lid = seat_plane_id;
List<SeatPlans> allUser = new List<SeatPlans>();
allUser = db.SEATPLAN.Where(d => d.layout_id == lid).ToList();
lid++;
List<SeatPlans> allUser1 = new List<SeatPlans>();
allUser1 = db.SEATPLAN.Where(d => d.layout_id == lid).ToList();
return new JsonResult { Data = allUser,JsonRequestBehavior = JsonRequestBehavior.AllowGet };
}
the code is working fine. 代码工作正常。 the controller action send the data in allUser to callback function.
控制器动作将allUser中的数据发送给回调函数。
but what i need is that i want to send both data in alluser and allUser1 to the success function of ajax call 但我需要的是,我想将alluser和allUser1中的数据发送到ajax调用的成功函数
I imagine you want to keep the lists separated. 我想你想要将列表分开。 Wrap them in an object.
将它们包裹在一个物体中。
var data = new { allUser = allUser , allUser1 = allUser1 };
return Json(yourObject, JsonRequestBehavior.AllowGet);
You can access them in your JS like this: 您可以在JS中访问它们,如下所示:
success: function (data) {
var allUser = data[0];
var allUser1 = data[1];
//use the data as you see fit.
loadData(allUser);
loadData(allUser1 );
},
You just have to modify your Where
clause so you don't need two different lists for the users. 您只需修改
Where
子句,这样就不需要为用户提供两个不同的列表。 Try this in your getdata
method: 在你的
getdata
方法中试试这个:
public JsonResult getdata(int seat_plane_id)
{
int lid = seat_plane_id;
List<SeatPlans> allUser = new List<SeatPlans>();
allUser = db.SEATPLAN.Where(d => d.layout_id == lid || d.layout_id == (lid+1)).ToList();
return new JsonResult { Data = allUser,JsonRequestBehavior = JsonRequestBehavior.AllowGet };
}
allUser
now includes all the desired data. allUser
现在包含所有需要的数据。
I would create a class that has 2 properties 我会创建一个具有2个属性的类
int lid = seat_plane_id;
List<List<SeatPlans>> listOfSeatPlans (a collection of collections)
List<List<SeatPlans>> list = new ...
list.Add(allUser);
list.Add(someUsers);
Now you can return the class object back to JSON 现在您可以将类对象返回给JSON
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