C＃格式字符串，我可以从中获取不同的值

Question

What is the best way to format the below string in a way so that I can separate out and find the value of PractitionerId, PhysicianNPI, PhysicianName etc.

"PractitionerId:4343343434 , PhysicianNPI: 43434343434, PhysicianName: John, Doe, PhysicianPhone:2222222222 , PhysicianFax:3333333333 "

So finally I want something like this:

var practitionerId = "4343343434 ";
var physNPI = "43434343434";
 var phyName = "John, Doe";

I was thinking of splitting with the names and finding the values assigned to each field but I am not sure if that is the best solution to it.

Answer 1

You could probably generalise this with a regular expression, then use it to build a dictionary/lookup of the terms.

So:

var input= "PractitionerId:4343343434 , PhysicianNPI: 43434343434,"
           + " PhysicianName: John, Doe, PhysicianPhone:2222222222 ,"
           + " PhysicianFax:3333333333";

var pattern = @"(?<=(?<n>\w+)\:)\s*(?<v>.*?)\s*((,\s*\w+\:)|$)";
var dic = Regex
              .Matches(input, pattern)
              .Cast<Match>()
              .ToDictionary(m => m.Groups["n"].Value, 
                            m => m.Groups["v"].Value);

So now you can:

var practitionerId = dic["PractitionerId"];

or

var physicianName = dic["PhysicianName"];

Answer 2

You could get the exact information, doing something like:

var str = "PractitionerId:4343343434 , PhysicianNPI: 43434343434, PhysicianName: John, Doe, PhysicianPhone:2222222222 , PhysicianFax:3333333333 ";

var newStr = str.Split(','); 

var practitionerID = newStr[0].Split(':')[1]; // "4343343434"
var physicianNPI = newStr[1].Split(':')[1].Trim(); // "43434343434"
var phyName = newStr[2].Split(':')[1].Trim() + "," + newStr[3]; // "John, Doe"

There are cleaner solutions using Regex patterns though.

Also, you need to parse the corresponding variables to the specific data type you want. Everything here is being treated as a string

Answer 3

Since you seperate information with ",", this should work:

   string[] information = yourWholeString.Split(",");
   string practitionerId = information[0];
   string physNPI = information[1];
   string phyName = information[2] + information[3];