[英]How to pass in an array from a script to main(args[])
I am writing a script that grabs some input from the user. 我正在编写一个脚本,可以从用户那里获取一些输入。 Right now I am have 3 varaibles: 2 strings and one array.
现在我有3个变量:2个字符串和一个数组。 I am able to pass in my 2 strings just fine to main, but I do not know how to pass in the array along with the rest.
我可以将我的2个字符串传递给main,但我不知道如何将数组与其余字符串一起传递。
This is what I have right now 这就是我现在所拥有的
java $myJava $var1 $var2 $array
Java's main accepts only an array of String, so var1 and var2 work just fine, but how can I pass in my array, which consists of variable number of inputs from the user? Java的main只接受一个String数组,因此var1和var2可以正常工作,但是如何传递我的数组,该数组由用户可变数量的输入组成? Is there a way that I can convert my array to numerous variables and then pass it into main?
有没有一种方法可以将数组转换为多个变量,然后将其传递给main?
If $array
is an actual Bash array (eg it was declared using declare -a array
, or another Bash array creation technique) then you just want to do 如果
$array
是一个实际的Bash数组(例如,它是使用declare -a array
或另一种Bash数组创建技术声明的),那么您只想做
java $myJava "$var1" "$var2" "${array[@]}"
That will extract the array into multiple positional arguments, so that the args
array that is passed into your main
will be 这会将数组提取到多个位置参数中,以便传递到您的
main
中的args
数组将是
{ var1 , var2 , array[0] , array[1] , array[2] , ... }
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