将指针设置为int值

Question

Why does the compiler complain when I try to set the value of a pointer to an int ? On my system, an int is the same size as a pointer. The int I have contains an address I want to set the pointer to.

int addr = 0xffff;
std::uint8_t* ptr = addr;

Why isn't this possible without casting addr ? Is the compiler trying to prevent me from shooting myself in the foot?

Answer 1

Because an int is not a std::uint8_t* . C++ is a typesafe language.