[英]/usr/bin/find: Argument list too long in for loop bash script
I have such a bash script. 我有这样的bash脚本。 I want to
gzip
all .ppm files under a directory to another directory. 我想将一个目录下的所有.ppm文件
gzip
压缩到另一个目录。 For this reason I have written such a bash script: 因此,我编写了这样的bash脚本:
cd /export/students/sait/12-may
for next_file in $(find . -type f ! -name *.ppm )
do
/bin/gzip -f -c $next_file > /export/students/sait/12-may-yedek/$next_file.gz
done
When I execute this script, I get such error: 执行此脚本时,出现以下错误:
/usr/bin/find: Argument list too long
How can I fix this problem? 我该如何解决这个问题?
Quote this part : *.ppm
to prevent filename globbing, and also remove the !
引用此部分:
*.ppm
以防止文件名*.ppm
,并删除!
as you want to find files with .ppm
extension, not the other way around. 因为您要查找扩展名为
.ppm
文件,而不是相反。
find . -type f -name '*.ppm'
find
command which would provide white space safety:
find
命令来执行此操作,以提供空白空间安全性:
find /export/students/sait/12-may -type f -name '*.ppm' -exec sh -c '/bin/gzip -f -c "$0" > "$0".gz' {} \\;
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