[英]How to replace substrings with strings from array using preg_replace? (PHP)
I have a data array containing these values: 我有一个包含这些值的数据数组:
Array
(
[id] => 1
[myid] => 9
[date] => 2014-01-30
[user] => 17
[reason] => some text here...
)
And this string which contains numbers referring to the data array indexes: 此字符串包含引用数据数组索引的数字:
$columns = '(0) as "id",(1) as "myid",(2) as "date",(3) as "user",(4) as "reason"';
Is it possible to change the numbers enclosed in brackets, including brackets to appropriate value from the array? 是否可以将括号中的数字(包括括号)更改为数组中的适当值?
I know how to work with (string) preg_replace( (array) $patterns, (array) $replacements, (string) $subject)
but quite don't know how to solve this problem. 我知道如何使用
(string) preg_replace( (array) $patterns, (array) $replacements, (string) $subject)
但不知道如何解决这个问题。
Ideally the result string could look like this: 理想情况下,结果字符串可能如下所示:
'1' as "id",'9' as "myid",'2014-01-30' as "date",'17' as "user",'some text here...' as "reason"
You can do it with a simple foreach
loop: 你可以用一个简单的
foreach
循环来做到这一点:
$info = array(
'id' => 1,
'myid' => 9,
'date' => '2014-01-30',
'user' => 17,
'reason' => 'some text here...'
);
$columns = '(0) as "id",(1) as "myid",(2) as "date",(3) as "user",(4) as "reason"';
foreach (array_values($info) as $key => $value) {
$columns = str_replace(
'(' . $key . ')',
str_pad($value, strlen($value) + 2, "'", STR_PAD_BOTH),
$columns
);
}
echo $columns;
The solution using preg_replace_callback
and str_replace
functions: 使用
preg_replace_callback
和str_replace
函数的解决方案:
$columns = '(0) as "id",(1) as "myid",(2) as "date",(3) as "user",(4) as "reason"';
// $arr is your initial array
$result = preg_replace_callback(
"/(\(\d\)) as \"(\w+?)\",?/i",
function ($maches) use($arr){
return str_replace([$maches[1]], "'". $arr[$maches[2]]. "'", $maches[0]);
},
$columns);
print_r($result);
The output: 输出:
'1' as "id",'9' as "myid",'2014-01-30' as "date",'17' as "user",'some text here...' as "reason"
You can do it using just some PHP library functions. 你可以使用一些PHP库函数来完成它。
$info = array(
'id' => 1,
'myid' => 9,
'date' => '2014-01-30',
'user' => 17,
'reason' => 'some text here...'
);
$columns = '(0) as "id",(1) as "myid",(2) as "date",(3) as "user",(4) as "reason"';
$new_Arr = array();
$column_arr = explode(",", $columns);
foreach($column_arr as $values){
$arr = explode(" as ", $values);
$new_Arr[] = "'".$info[trim($arr[1], '"')]."' as ".$arr[1];
}
echo implode(",", $new_Arr) //'1' as "id",'9' as "myid",'2014-01-30' as "date",'17' as "user",'some text here...' as "reason"
Just use a loop with str_replace. 只需使用带有str_replace的循环。 Iterate through array, use loop index in brackets as a search string and replace it with corrsponding value.
迭代数组,使用括号中的循环索引作为搜索字符串,并将其替换为corrsponding值。
array_flip is your saviour
array_flip是你的救世主
Straight from docs 直接来自文档
<?php
$input = array("oranges", "apples", "pears");
$flipped = array_flip($input);
print_r($flipped);
?>
The above example will output: 上面的例子将输出:
Array
(
[oranges] => 0
[apples] => 1
[pears] => 2
)
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