如果我的计算机是32位系统，则它具有32位地址，对吗？ 但是，当我在C中打印任何内存地址时，为什么我得到的地址<32bit？

Question

For example

printf("%u",&a);

gives me output

65524

which is a 16 bit address.

Answer 1

Because you used wrong format specifier which invokes undefined behavior .

To print a pointer, you should use %p format specifier and cast the argument to void* . Something like

 printf("%p",(void *)&a);

will do the job.

That said, you should look into the concepts of virtual memory the first thing.

Answer 2

You can also simply answer your assumption about address size by checking the size of any pointer instead of a test variable's address:

printf("%zu\n", sizeof(int*));
printf("%zu\n", sizeof(float*));

Assuming that a byte in all systems equals eight bit, you can see about size of address.

Please see this SO post

Answer 3

To find the highest possible address for (most of) the currently common systems do this:

#include <stdint.h>
#include <stdio.h>

int main(void)
{
  uintptr_t uip = (uintptr_t) -1;
  void * vp = (void*) uip;

  printf("%p\n", vp);
}