mysql一个依赖于其他的

Question

I want to make count of products which has been disabled and have options. First I try to check in one table oc_product are product is disabled and then I want to check by this status (if disabled product) and product id check in another table are this product id have options.

I try like this, but thus only show result of status=0 products.

select COUNT(*) 
FROM oc_product 
WHERE status=0 
  AND product_id IN ( SELECT product_id FROM oc_product_option)

Answer 1

If I unrestood your question, you want to join the tables.

SELECT COUNT(*) FROM oc_product ocp
INNER JOIN oc_product_option ocpo ON ocpo.product_id = ocp.id
WHERE ocp.status=0 

so only those rows will returns where product_id in option table ( ocpo.product_id = ocp.id )

Answer 2

If I understand correctly, you want a count of all the products with status 0, and also a count of all the products with a status of 0 which have options.

If so, LEFT OUTER JOIN products with options. Then you can count the DISTINCT product_id from the products table to get the count of product, and you can count the DISTINCT product_id from the product options table to get a count of the products with options. COUNT(column_name) doesn't count rows where the column_name value is NULL, hence won't count products where no matching options were found.

SELECT COUNT(DISTINCT oc_product.product_id) AS product_count,
        COUNT(DISTINCT oc_product_option.product_id) AS product_with_options_count
FROM oc_product 
LEFT OUTER JOIN oc_product_option
ON oc_product.product_id = oc_product_option.product_id
WHERE oc_product.status = 0