如何将逗号和分号分隔的字符串拆分为二维数组

Question

Let's say I have a variable users that contains the following string of text where each user is separated by a semicolon and each attribute of each users is separated by a comma:

Bob,1234,Bob@example.com;Mark,5678,Mark@example.com

How would I split this into a multidimensional array variable userArray that looks like this:

[
    [Bob,1234,Bob@example.com],
    [Mark,5678,Mark@example.com]
]

using JavaScript?

Answer 1

You can do this with split() and map()

var str = 'Bob,1234,Bob@example.com;Mark,5678,Mark@example.com';
var result = str.split(';').map(e => e.split(','));
console.log(result)

Answer 2

You just have to split is twice. First by ';' , and then each element of the resulting array by ',' . Something like this:

"Bob,1234,Bob@example.com;Mark,5678,Mark@example.com"
    .split(';')
    .map(function(sub) { 
        return sub.split(',') 
    });

Just run the above snippet in your browser console, and you'll see:

[
  Array[3]0: "Bob"1: "1234"2: "Bob@example.com"length: 3__proto__: Array[0],
  Array[3]0: "Mark"1: "5678"2: "Mark@example.com"length: 3__proto__: Array[0]
]

Answer 3

you just do

 var users = 'Bob,1234,Bob@example.com;Mark,5678,Mark@example.com'; var userInfo = users.split(';'); for (var i = 0, len = userInfo.length; i < len; i++) { userInfo[i] = userInfo[i].split(','); } console.log('userInfo', userInfo);

Answer 4

You can split by semicolon first and then by comma.

 var str = 'Bob,1234,Bob@example.com;Mark,5678,Mark@example.com', array = str.split(';').map(function (a) { return a.split(','); }); console.log(array);

ES6

 var str = 'Bob,1234,Bob@example.com;Mark,5678,Mark@example.com', array = str.split(';').map(a => a.split(',')); console.log(array);

Answer 5

var arr = [];
var string = 'Bob,1234,Bob@example.com;Mark,5678,Mark@example.com';
var users = string.split(';')
for(var user in users)
      arr.push(users[user].split(','));
JSON.stringify(arr);

Answer 6

If you are looking for a one liner that puts every elements in an array.

Here is a solution:

b.split(';').map(e => e.split(',')).reduce((acc, cur) => cur.concat(acc), []).filter(e => !!e)