[英]Iterating through json array with appended json string in android after json as response from url using volley
Hi i am trying to iterate through a json string that looks like this: 嗨,我想迭代一个看起来像这样的json字符串:
{
"vendor":[
{
"vendor_name":"Tapan Moharana",
"vendor_description":"",
"vendor_slug":"tapan",
"vendor_logo":null,
"contact_number":null
}
],
"products":
{
"25":
{
"name":"Massage",
"price":"5000.0000",
"image":"http:\/\/carrottech.com\/lcart\/media\/catalog\/product\/cache\/1\/image\/150x\/9df78eab33525d08d6e5fb8d27136e95\/2\/9\/29660571-beauty-spa-woman-portrait-beautiful-girl-touching-her-face.jpg"
},
"26":
{
"name":"Chicken Chilly",
"price":"234.0000",
"image":"http:\/\/carrottech.com\/lcart\/media\/catalog\/product\/cache\/1\/image\/150x\/9df78eab33525d08d6e5fb8d27136e95\/c\/h\/cheicken.jpg"
},
"27":
{
"name":"Chicken Biryani",
"price":"500.0000",
"image":"http:\/\/carrottech.com\/lcart\/media\/catalog\/product\/cache\/1\/image\/150x\/9df78eab33525d08d6e5fb8d27136e95\/placeholder\/default\/image_1.jpg"
}
}
}
here is a better view of the json string: 这里是json字符串的更好视图:
I am iterating through the vendor array of this json string using this code: 我正在使用以下代码遍历此json字符串的供应商数组:
JSONObject jsono = new JSONObject(response);
JSONArray children = jsono.getJSONArray("vendor");
for (int i = 0; i <children.length(); i++) {
JSONObject jsonData = children.getJSONObject(i);
System.out.print(jsonData.getString("vendor_name") + "<----");
// String vendorThumbNailURL=jsonData.getString("")
//jvendorImageURL.setImageUrl(local, mImageLoader);
vendorLogo=vendorLogo+jsonData.getString("vendor_logo").trim();
jvendorImageURL.setImageUrl(vendorLogo, mImageLoader);
jvendorName.setText(jsonData.getString("vendor_name"));
jvendorAbout.setText(jsonData.getString("vendor_description"));
jvendorContact.setText(jsonData.getString("contact_number"));
}
but I dont know how to get data from the "products" object please help me how do i set my json objects to iterate through "products" 但我不知道如何从“产品”对象获取数据请帮助我如何设置我的json对象迭代“产品”
when i try to change the format of the array so that both products and vendor are a separate json array i still get the above json format.. 当我尝试更改阵列的格式,以便产品和供应商都是一个单独的json数组时,我仍然得到上面的json格式..
this is what i am doing 这就是我在做的事情
$resp_array['vendor'] = $info;
$resp_array['products'] = $vendorProductsInfo;
$resp_array = json_encode($resp_array);
print_r($resp_array);
please help me with this 请在这件事上给予我帮助
MODIFIED QUESTION: 修改后的问题:
I have modified my web response like this: 我修改了我的网络响应,如下所示:
[{"entity_id":24,"product_name":"Burger","product_image_url":"\/b\/u\/burger_large.jpg","price":"234.0000","category_id":59},{"entity_id":27,"product_name":"Chicken Biryani","product_image_url":"\/b\/i\/biryani.jpg","price":"500.0000","category_id":59},{"entity_id":31,"product_name":"Pizza","product_image_url":"\/p\/i\/pizza_png7143_1.png","price":"125.0000","category_id":59}]
and the code: 和代码:
JSONArray children = jsono.getJSONArray("vendor");
for (int i = 0; i <children.length(); i++) {
JSONObject jsonData = children.getJSONObject(i);
System.out.print(jsonData.getString("vendor_name") + "<----");
// String vendorThumbNailURL=jsonData.getString("")
//jvendorImageURL.setImageUrl(local, mImageLoader);
vendorLogo=vendorLogo+jsonData.getString("vendor_logo").trim();
jvendorImageURL.setImageUrl(vendorLogo, mImageLoader);
jvendorName.setText(jsonData.getString("vendor_name"));
jvendorAbout.setText(jsonData.getString("vendor_description"));
jvendorContact.setText(jsonData.getString("contact_number"));
System.out.print(jsonData.getString("products") + "<----");
}
JSONObject jsono1 = new JSONObject(response);
JSONArray childrenProducts = jsono1.getJSONArray("products");
for(int i=0;i<childrenProducts.length();i++){
JSONObject jsonData = childrenProducts.getJSONObject(i);
System.out.print(jsonData.getString("name") + "<----dd");
}
but still the products part is not working... please help 但仍然产品部分不起作用...请帮助
Here is the working solution: Using GOOGLE GSON (Open source jar) 这是工作解决方案:使用GOOGLE GSON(开源jar)
import java.io.IOException;
import com.google.gson.Gson;
import com.google.gson.GsonBuilder;
public class JsonToJava {
public static void main(String[] args) throws IOException {
try{
String json = "<YOUR_JSON>";
Gson gson = new GsonBuilder().create();
VendorInfo vInfo = gson.fromJson(json, VendorInfo.class);
System.out.println(vInfo.getVendorName());
} catch(Exception ex) {
ex.printStackTrace();
}
}
}
Create classes for Vendor and Product 为供应商和产品创建类
public class Vendor {
public String vendor_name;
public String vendor_description;
public String vendor_slug;
public String vendor_logo;
public String contact_number;
public String getName() {
return vendor_name;
}
}
public class Product {
public String name;
public long price;
public String image;
public String getName() {
return name;
}
}
VendorInfo is the JSON object form: VendorInfo是JSON对象形式:
import java.util.Map;
public class VendorInfo {
public Vendor[] vendor;
public Map<Integer, Product> products;
public String getVendorName() {
return vendor[0].getName();
}
public Product getProduct() {
System.out.println(products.size());
return products.get(25);
}
}
You can add your getters for Vendor, Product and VendorInfo. 您可以为Vendor,Product和VendorInfo添加getter。 You are done!
你完成了! You will get all the data.
您将获得所有数据。
Output of JsonToJava: JsonToJava的输出:
Tapan Moharana
To get your products data , you need to use Iterator
要获取产品数据,您需要使用
Iterator
JSONObject jProducts = jsonObject
.optJSONObject("products");
try {
if (jProducts
.length() > 0) {
Iterator<String> p_keys = jProducts
.keys();
while (p_keys
.hasNext()) {
String keyProduct = p_keys
.next();
JSONObject jP = jProducts
.optJSONObject(keyProduct);
if (jP != null) {
Log.e("Products",
jP.toString());
}
}
}
} catch (Exception e) { // TODO:
// handle
// exception
}
you can try with this 你可以试试这个
JSONObject jsono = null;
try {
jsono = new JSONObject(response);
JSONObject productObject = jsono.getJSONObject("products");
Iterator<String> keys = productObject.keys();
while (keys.hasNext())
{
// get the key
String key = keys.next();
// get the value
JSONObject value = productObject.getJSONObject(key);
//get seprate objects
String name = value.getString("name");
String image = value.getString("image");
Log.i(TAG,name+"-"+image);
}
}
catch (JSONException e) {
e.printStackTrace();
}
Try this : 试试这个 :
JSONObject productObject = jsono.getJSONObject("products");
JSONObject json_25 = productObject getJSONObject("25");
String name_25= json_25.getString("name");
String price_25= json_25.getString("price");
String image_25= json_25.getString("image");
JSONObject json_26 = productObject getJSONObject("26");
String name_26= json_26.getString("name");
String price_26= json_26.getString("price");
String image_26= json_26.getString("image");
JSONObject json_27 = productObject getJSONObject("27");
String name_27= json_27.getString("name");
String price_27= json_27.getString("price");
String image_27= json_27.getString("image");
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