在MySQL中进行COUNT查询后，如何简化重复列的结果？

Question

I have a query that create an a Count with INNER JOIN's over a Query in MySQL, but I need to SUM the rows repeated after did this query in the TOTAL column. The MySQL query is:

SELECT COUNT(*) AS TOTAL,
    usuarios.nombres_user AS NOMBRE
FROM usuarios
INNER JOIN usuarios_login ON usuarios.id_user = usuarios_login.id_user
INNER JOIN roles ON usuarios_login.id_rol_login = roles.id_rol
INNER JOIN actividades ON actividades.usuario_actividad = usuarios_login.id_login
INNER JOIN prospectos ON prospectos.Id_prospecto = actividades.id_prospecto_actividad
INNER JOIN familias_prospectos ON familias_prospectos.Id_familia_prospecto = prospectos.familia_prospecto_id
INNER JOIN campus ON campus.id_camp = familias_prospectos.id_campus_familias_prospectos
WHERE roles.nombre_rol LIKE '%CRM%'
  AND campus.id_camp = 2
GROUP BY (usuarios_login.id_login), prospectos.Id_prospecto
ORDER BY usuarios.nombres_user ASC

This query give me the total count of a user in a column with a GROUP BY and only the TOTAL and NOMBRE values. So, after a did this, I want to simplify the query, like (this is an example that my query did before):

My Query give me:
-----------------
TOTAL | NOMBRE
-----------------
   2     John
   1     John
   4     John
   6     Peter
   3     Peter
   1     Peter
   4     Robert
   2     Robert    
And the Goal is try to get:
-----------------
TOTAL | NOMBRE
-----------------
   7     John
   10    Peter
   6     Robert

I'm working in PHP and MySQL, there is a way too make it directly with a query in MySQL? I've hope you help me. Thank you.

Answer 1

You probably should use HAVING .

SELECT
  COUNT(*)              AS TOTAL,
  usuarios.nombres_user AS NOMBRE
FROM usuarios
  INNER JOIN usuarios_login ON usuarios.id_user = usuarios_login.id_user
  INNER JOIN roles ON usuarios_login.id_rol_login = roles.id_rol
  INNER JOIN actividades ON actividades.usuario_actividad = usuarios_login.id_login
  INNER JOIN prospectos ON prospectos.Id_prospecto = actividades.id_prospecto_actividad
  INNER JOIN familias_prospectos ON familias_prospectos.Id_familia_prospecto = prospectos.familia_prospecto_id
  INNER JOIN campus ON campus.id_camp = familias_prospectos.id_campus_familias_prospectos
GROUP BY (usuarios_login.id_login), prospectos.Id_prospecto
HAVING roles.nombre_rol LIKE '%CRM%' AND campus.id_camp = 2
ORDER BY usuarios.nombres_user ASC

Answer 2

You get duplicates users because you make your GROUP BY on 2 values: id_login and Id_prospecto

You can better understand your result if you add the 2 fields you are grouping on in your SELECT statement, like this

SELECT COUNT(*) AS TOTAL,
    usuarios.nombres_user AS NOMBRE, usuarios_login.id_login, prospectos.Id_prospecto
FROM usuarios
INNER JOIN usuarios_login ON usuarios.id_user = usuarios_login.id_user
INNER JOIN roles ON usuarios_login.id_rol_login = roles.id_rol
INNER JOIN actividades ON actividades.usuario_actividad = usuarios_login.id_login
INNER JOIN prospectos ON prospectos.Id_prospecto = actividades.id_prospecto_actividad
INNER JOIN familias_prospectos ON familias_prospectos.Id_familia_prospecto = prospectos.familia_prospecto_id
INNER JOIN campus ON campus.id_camp = familias_prospectos.id_campus_familias_prospectos
WHERE roles.nombre_rol LIKE '%CRM%'
  AND campus.id_camp = 2
GROUP BY (usuarios_login.id_login), prospectos.Id_prospecto
ORDER BY usuarios.nombres_user ASC

Without seeing your data I'll only make a guess: if you want the total per user, just remove prospectos.Id_prospecto from the GROUP BY so the data will stay grouped at user level :

SELECT COUNT(*) AS TOTAL,
    usuarios.nombres_user AS NOMBRE
FROM usuarios
INNER JOIN usuarios_login ON usuarios.id_user = usuarios_login.id_user
INNER JOIN roles ON usuarios_login.id_rol_login = roles.id_rol
INNER JOIN actividades ON actividades.usuario_actividad = usuarios_login.id_login
INNER JOIN prospectos ON prospectos.Id_prospecto = actividades.id_prospecto_actividad
INNER JOIN familias_prospectos ON familias_prospectos.Id_familia_prospecto = prospectos.familia_prospecto_id
INNER JOIN campus ON campus.id_camp = familias_prospectos.id_campus_familias_prospectos
WHERE roles.nombre_rol LIKE '%CRM%'
  AND campus.id_camp = 2
GROUP BY (usuarios_login.id_login)
ORDER BY usuarios.nombres_user ASC

If this don't work, you can simply SUM the totals with another query :

SELECT SUM(TOTAL), NOMBRE
FROM
(   
        SELECT COUNT(*) AS TOTAL,
        usuarios.nombres_user AS NOMBRE
    FROM usuarios
    INNER JOIN usuarios_login ON usuarios.id_user = usuarios_login.id_user
    INNER JOIN roles ON usuarios_login.id_rol_login = roles.id_rol
    INNER JOIN actividades ON actividades.usuario_actividad = usuarios_login.id_login
    INNER JOIN prospectos ON prospectos.Id_prospecto = actividades.id_prospecto_actividad
    INNER JOIN familias_prospectos ON familias_prospectos.Id_familia_prospecto = prospectos.familia_prospecto_id
    INNER JOIN campus ON campus.id_camp = familias_prospectos.id_campus_familias_prospectos
    WHERE roles.nombre_rol LIKE '%CRM%'
      AND campus.id_camp = 2
    GROUP BY (usuarios_login.id_login), prospectos.Id_prospecto
) T
GROUP BY NOMBRE
ORDER BY NOMBRE ASC