如何在Python列表列表中从字符串中生成数字列表

Question

I have a list like this:

[[['(0,1,2)','(3,4,5)'],['(5,6,7)','(9,4,2)']],[['(0,1,2)','(3,4,5)'],['(5,6,7)','(9,4,2)']]]

And I would like to get something like:

[[[[0,1,2],[3,4,5]],[[5,6,7],[9,4,2]]],[[[0,1,2],[3,4,5]],[[5,6,7],[9,4,2]]]

I've tried string comprehension, the re module, splitting, stripping but none seem to work. Thanks!

Answer 1

Recursion seems quite straightforward:

l = [[['(0,1,2)','(3,4,5)'],['(5,6,7)','(9,4,2)']],[['(0,1,2)','(3,4,5)'],['(5,6,7)','(9,4,2)']]]

def convert(x):
    if isinstance(x, list):
        return [convert(y) for y in x]
    else:
        return [int(y) for y in x.strip('()').split(',')]

convert(l) # [[[[0, 1, 2], [3, 4, 5]], [[5, 6, 7], [9, 4, 2]]], [[[0, 1, 2], [3, 4, 5]], [[5, 6, 7], [9, 4, 2]]]]

Answer 2

In case you want to see what it looks like in nested list comprehensions

startList = [[['(0,1,2)','(3,4,5)'],['(5,6,7)','(9,4,2)']],[['(0,1,2)','(3,4,5)'],['(5,6,7)','(9,4,2)']]]
new = [[[[int(x) for x in moreSub.strip("()").split(",")] for moreSub in subitem] for subitem in item] for item in startList]
print(new)