使用 Scanner 类输入

Question

I am a new java programmer, In my below code when am trying to enter the employee name like john smith, only john is getting printed in output. And if I put

System.out.print("Enter Employee Name: ");   
String employeeName = s.next(); 

above

System.out.print("Enter SEX: ");       
char SEX = s.next().charAt(0);

this piece of code in output is not asking for my employeename value. and directly printing the remaining values.

/*
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 * and open the template in the editor.
 */
**package cs480;
import java.util.Scanner;
public class CS480D1_Richa_2_Week2 {
    public static void main(String [] args){
     Scanner s=new Scanner(System.in);  
     System.out.print("Ente Employee ID: ");
     int employeeId = s.nextInt();
     System.out.print("Ente SEX: ");       
     char SEX = s.next().charAt(0);
     System.out.print("Ente Employee Name: ");
     String employeeName = s.next();
     System.out.println("Employee ID is " +employeeId);
     System.out.println("Employee Name is " +employeeName);
     System.out.println("Employee gender is " +SEX);
    }        

}**

Answer 1

Try replacing your code

String employeeName = scanner.nextLine();

instead

String employeeName = scanner.next();

next() can read the input only till the space. It can't read two words separated by space. Also, next() places the cursor in the same line after reading the input.

nextLine() reads input including space between the words (that is, it reads till the end of line \\n). Once the input is read, nextLine() positions the cursor in the next line.

Answer 2

Either you can use

scanner.nextLine()

or override delimiter to use next()

scanner.useDelimiter("\n");
scanner.next();

Answer 3

Please try with this:

public static void main(String[] args) {

    Scanner s = new Scanner(System.in);
    System.out.print("Ente Employee ID: ");
    int employeeId = s.nextInt();
    System.out.print("Ente SEX: ");
    char SEX = s.next().charAt(0);
    System.out.print("Ente Employee Name: ");
    String employeeName = s.nextLine();
    employeeName = s.nextLine();// Try to add this line of code
    System.out.println("Employee ID is " + employeeId);
    System.out.println("Employee Name is " + employeeName);
    System.out.println("Employee gender is " + SEX);

}

Answer 4

Scanner.next() uses a white-space delimiter(takes the element before white-space).

So either use

Scanner.nextLine() 

or reset the delimiter using

Scanner s = new Scanner(input).useDelimiter("\\s*"your delimiter"\\s*");