如何在bash中比较两个awk结果值

Question

Here's my code:

#!/bin/bash
filename=$1

declare -a myarr
myarr=($(awk '{print $2}' sim.count))
for((i=0 ;i<${#myarr[@]};i++))
do
#echo ${myarr[$i]}
#rm  "${myarr[$i]}"
awk '{if ($1 == "{$myarr[$i]}"){print $2}}' $filename > "${myarr[$i]}"
done

I store awk result into array and run loop to find if $filename 's column one has the same element then print column two

I have tried if ($1 == "a|||a"){print $2} and it work well, but if ($1 == "{$myarr[$i]}") not the result I want, anything wrong ??

Answer 1

This is literally comparing against {$myarr[i]} , not against the value associated with an entry in the shell variable by that name:

# original code: DOES NOT WORK (even if fixed to ${myarr[$i]})
awk '{if ($1 == "{$myarr[$i]}"){print $2}}'

This is because the double-quotes are still inside single-quotes, so the string is passed to awk without the shell expanding it -- and awk has no way of looking at shell variables (except ones in the environment, which requires explicit syntax to look up and doesn't apply to arrays anyhow).

---

Instead, pass your expanded value into awk separately:

awk -v tgt="${myarr[i]}" '{if ($1 == tgt) {print $2}}'