如何通过批处理获取最新版本的Java

Question

I have to create a batch program that verifies a correct JDK install. I have already created a simple java program that, when run, outputs conformation that the JDK has been installed. The program must also, however, set the path to the new JDK. I know that the java file will be in c:\\Program Files\\java\\jdk1.8.0_##\\bin , where ## is one of about 10 diffrent numbers. Is there any way I can search the directory c:\\Program Files\\java for folders beginning with jdk1.8.0 such that I could set a variable to the appropriate filename? There are other files in the c:\\Program Files\\java directoy, including previous JDKs and JREs.

echo Initializing...
set current=%cd% //get current directory
cd c:\Program Files\java //navigate to java directory
set java= //Files formated jdk1.8.0_...
cd %current% //return directory to local (JavaDemo is located here)
set path=%java% //Set path for javac
javac JavaDemo.java //compile JavaDemo
java JavaDemo //run JavaDemo

Thanks in advance! Know you guys are a huge help

Answer 1

You could use the dir command with sort options : dir command

and go through the results with :

for /F %%x in ('dir /B/D %MYDIR%') do ( set PATH=%MYDIR%)

and choose the right one with a if statement