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使用bash脚本创建文件夹和文件

[英]Folder and File creating with bash scripting

I have to create 50 folders and each fifth folder should have 2*2 files in it, eg 我必须创建50个文件夹,每个第五个文件夹中应该有2 * 2个文件,例如

folder1
.
.
folder5 - has 2 files in it
folder 6
.
.
folder 10 - has 4 files in it 
.
.
folder 15 - has 8 files in it 

here is my code : 这是我的代码:

#!/bin/bash


n=1 
declare -i countFolder

for (( countFolder = 1; countFolder <= 50; countFolder++ )) 
do 
    mkdir Folder$countFolder
done

for (( countFolder = 5; countFolder <= 50; countFolder = countFolder+5 ))
do

    let "n = n * 2"

    for (( f = 0; f < n; f++ )) do
    cd Folder$countFolder && touch File$f.txt
    done
done

The problem with this is that you cd into a directory but you never cd back. 这里的问题是,你cd到一个目录,但你永远cd回来。

The simplest way of fixing this is by adding parentheses around the cd . 解决此问题的最简单方法是在cd周围添加括号。 These parentheses start a subshell, so the cd stays within it: 这些括号开始一个子shell,因此cd保留在其中:

for (( f = 0; f < n; f++ )) do
  ( cd Folder$countFolder && touch File$f.txt ) 
done

This is equivalent to but shorter than a manual cd .. : 这相当于但比手动cd ..cd ..

for (( f = 0; f < n; f++ )) do
  cd Folder$countFolder && { touch File$f.txt; cd ..; }
done

You need to go into the directory, make your files, then leave. 您需要进入目录,制作文件,然后离开。 The most efficient way to do this is the following: 最有效的方法如下:

#!/bin/bash


n=1 
declare -i countFolder

for (( countFolder = 1; countFolder <= 50; countFolder++ )) 
do 
    mkdir Folder$countFolder
    ls
done

for (( countFolder = 5; countFolder <= 50; countFolder = countFolder+5 ))
do

    let "n = n * 2"
    cd Folder$countFolder
    for (( f = 0; f < n; f++ )) do
        touch File$f.txt
    done
    cd ..
done

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