配置单元查询以从表中删除最小值

Question

I have a table with schema t( a ,b,c) in hive. I have to select all the rows whose a is not the minimum in t

I tried

select * from t where a>(select min(a) from t limit 1);

select * from t where t.a not in (select min(a) from t limit 1);

both of them failed .. How can I achieve this in hive and what is the generalization of error in above statements?

Edit : with , IN , exists are not supported in my hive version .. so please refrain from using these in your answer

Answer 1

try the below query

select A.* from t A left join (select min(a) as min from t) B where Aa>B.min

Subqueries inside a WHERE clause are not supported in Hive

check this Write a nested select statement with a where clause in Hive

i think the new version supports subqueries

Thanks