接收java.sql.SQLException：调用数据库函数时无效的列索引错误

Question

I am trying to invoke a database function using callable statement. The signature of the Stored Procedure is given below;

 function DUMMY_FUNCTION (PARAM1          in    Number
                               ,PARAM2    in    Number
                               ,PARAM3 in    varchar2
                               ,PARAM4          in    Number
                               ,PARAM5           in    Date
                               ,PARAM6          in    Number 
                               ,PARAM7         out    varchar2
                               ,PARAM8           out    varchar2) 

return varchar2;

and the JAVA code for invoking is as below:

 //Load SQl Binaries import java.sql.CallableStatement; import java.sql.Connection; import java.sql.Date; import java.sql.DriverManager; import java.text.SimpleDateFormat; public class InvokeProcedure { public static String callProcedure(int PARAM1,int PARAM2,String PARAM3,int PARAM4,String PARAM5,int PARAM6) throws Exception { //Defining Parameters String result = new String(); Connection conn = null; CallableStatement cs = null; String outParam = null; SimpleDateFormat sdf=new SimpleDateFormat("yyyy-MM-dd"); try { conn = getDBConnection(); String proc3Function = "{? = call P1SCHEMA.DUMMY_PACKAGE.DUMMY_FUNCTION(?, ?, ?, ?, ?, ?) }"; conn.setAutoCommit(false); cs = conn.prepareCall(proc3Function); java.sql.Date param5date = new java.sql.Date( sdf.parse(PARAM5).getTime() ); //DefiningInput Parameters cs.setInt(1, PARAM1); cs.setInt(2, PARAM2); cs.setString(3, PARAM3); cs.setInt(4, PARAM4); cs.setDate(5, param5date); cs.setInt(6, PARAM6); //Defining Output Parameters cs.registerOutParameter(7, java.sql.Types.VARCHAR); cs.registerOutParameter(8, java.sql.Types.VARCHAR); cs.registerOutParameter(9, java.sql.Types.VARCHAR); //Execute Statement cs.execute(); //Capture Output outParam = cs.getString(8); String I = new String(outParam); //Set Resultant Array result = I.toString() + "###" + cs.getString(7) + "###" + cs.getString(8) + "###" + cs.getString(9); //Check the Reason Code Returned from Stored Procedure if (outParam == "S") { //Roll back Transaction conn.rollback(); } else { //Commit Transaction conn.commit(); } } catch (Exception e) { e.printStackTrace(); } finally { if (cs != null) { //Close Connection cs.close(); } if (conn != null) { //Close Connection conn.close(); } } // Return Array to Client return result; } public static Connection getDBConnection() throws Exception { String driver = "oracle.jdbc.xa.client.OracleXADataSource"; String url = "jdbc:oracle:thin:@localhost:1539:DEV"; String username = "user"; String password = "password"; Class.forName(driver); Connection conn = DriverManager.getConnection(url, username, password); return conn; } public static void main(String args[]) throws Exception{ InvokeProcedure INP = new InvokeProcedure(); String Args = INP.callProcedure(1,2,"A",3,"2016-01-23",4); System.out.println(Args); } }

While running the java program I am getting the below exception, not sure where i am doing wrong

java.sql.SQLException: Invalid column index
at oracle.jdbc.driver.SQLStateMapping.newSQLException(SQLStateMapping.java:70)
at oracle.jdbc.driver.DatabaseError.newSQLException(DatabaseError.java:133)
at oracle.jdbc.driver.DatabaseError.throwSqlException(DatabaseError.java:199)
at oracle.jdbc.driver.DatabaseError.throwSqlException(DatabaseError.java:263)
at oracle.jdbc.driver.DatabaseError.throwSqlException(DatabaseError.java:271)
at oracle.jdbc.driver.DatabaseError.throwSqlException(DatabaseError.java:445)
at oracle.jdbc.driver.OracleCallableStatement.registerOutParameterInternal(OracleCallableStatement.java:122)
at oracle.jdbc.driver.OracleCallableStatement.registerOutParameter(OracleCallableStatement.java:288)
at oracle.jdbc.driver.OracleCallableStatement.registerOutParameter(OracleCallableStatement.java:379)
at oracle.jdbc.driver.OracleCallableStatementWrapper.registerOutParameter(OracleCallableStatementWrapper.java:1568)

Thanks

Answer 1

The function has 8 parameters, but the call has only six (?, ?, ?, ?, ?, ?) :

"{? = call P1SCHEMA.DUMMY_PACKAGE.DUMMY_FUNCTION(?, ?, ?, ?, ?, ?) }";

Use:

"{? = call P1SCHEMA.DUMMY_PACKAGE.DUMMY_FUNCTION(?, ?, ?, ?, ?, ?, ?, ?) }";

An then - the positional parameters ? are numbered from left to right.
:

• {? = {? = - this is the first parameter, it's index is 1,
  use cs.registerOutParameter( 1, java.sql.Types.SomeType)
• (?, ?, ?, ?, ?, ?, ?, ?) there are consecutively 2,3,4,....8,9 parameters

Use:

cs.setInt(2, PARAM1);
cs.setInt(3, PARAM2);
cs.setString(4, PARAM3);
...

Two last parameters with indexes: 8,9 are OUT parameter - register them using:

cs.registerOutParameter(8, java.sql.Types.VARCHAR);
cs.registerOutParameter(9, java.sql.Types.VARCHAR);

Answer 2

Sorry, missed it since it was out of snippet. I suppose you need to register output parameter first since you have statement '? = ...' so it will be cs.registerOutParameter(1, java.sql.Types.VARCHAR); and then other parameters without last one of course by Stan