如何获得任何特定的进程窗口大小？

Question

I tried this in top of form1

[DllImport("user32.dll", CharSet = CharSet.Auto)]
public static extern IntPtr FindWindow(string strClassName, string strWindowName);

[DllImport("user32.dll")]
public static extern bool GetWindowRect(IntPtr hwnd, ref Rect1 rectangle);

public struct Rect1
{
    public int Left { get; set; }
    public int Top { get; set; }
    public int Right { get; set; }
    public int Bottom { get; set; }
}

Then in constructor

Process[] processes1 = Process.GetProcessesByName("mspaint");
Process lol = processes1[0];
IntPtr ptr = lol.MainWindowHandle;
Rect1 mspaintRect = new Rect1();
GetWindowRect(ptr, ref mspaintRect);

But the result is strange I think. In mspainRect using a break point I see

Bottom = -31972
Left = -32000
Right = -31840
Top = -32000

Answer 1

When a window is minimized the location of windows is {X=-32000,Y=-32000} . So it seems in your example case, window of mspaint is minimized.

The reason behind this strange coordinates is because of backward compatibility with some old versions of Windows.

Where did windows minimize to before the taskbar was invented?

Windows NT stuck with the -32000 coordinates and didn't pick up the compatibility fixes for some reason. I guess they figured that by the time Windows NT became popular, all those broken programs would have been fixed.