[英]Compare two arraylists in java which have partial common values
I have one array list having values as:我有一个数组列表,其值为:
IT Infrastructure
IT基础设施
Teams团队
Wave Analytics Starter KitWave 分析入门套件
Blog Post博客文章
Case Studies实例探究
InfoGraphics信息图表
Grazitti Site Development-RevampGrazitti 网站开发-改造
and another array list having values as:另一个数组列表的值为:
Wave Analytics Starter Kit56:00:00
Wave Analytics 入门套件56:00:00
IT Infrastructure01:00:00IT基础设施01:00:00
Teams08:00:00团队08:00:00
Blog Post21:30:00博文21:30:00
Case Studies02:30:00案例研究02:30:00
InfoGraphics02:45:00信息图表02:45:00
Grazitti Site Development-Revamp11:00:00Grazitti 网站开发-改造11:00:00
Content Marketing03:00:00内容营销03:00:00
Off-Page Content04:30:00页外内容04:30:00
SMM05:00:00SMM05:00:00
Guest Blog01:30:00来宾博客01:30:00
LiNC 1600:30:00连线 1600:30:00
Alteryx Inspire Conference 201625:30:00Alteryx 启发大会 201625:30:00
PPC02:00:00PPC02:00:00
Training13:45:00培训13:45:00
Can I compare them to get the output as:我可以比较它们以获得输出为:
IT Infrastructure01:00:00
IT基础设施01:00:00
Teams08:00:00团队08:00:00
Wave Analytics Starter Kit56:00:00Wave Analytics 入门套件56:00:00
Blog Post21:30:00博文21:30:00
Case Studies02:30:00案例研究02:30:00
InfoGraphics02:45:00信息图表02:45:00
Grazitti Site Development-Revamp11:00:00Grazitti 网站开发-改造11:00:00
The following piece of code isn't giving the desired ouput:以下代码没有给出所需的输出:
for(int c =0; c<extractedvalue.size(); c++){
System.out.println(extractedvalue.get(c));
if (extractedvalue.contains(hoursplusprojects.get(c))){
System.out.println(hoursplusprojects.get(c));
}
Here is a solution in O(nm).这是一个 O(nm) 的解决方案。 n and m are the sizes of your arrays.
n 和 m 是数组的大小。 The solution works for the case that the two arrays have the structure that you illustrated in your question.
该解决方案适用于两个数组具有您在问题中说明的结构的情况。
List<String> l1 = new ArrayList<String>();
//update l1
List<String> l2 = new ArrayList<String>();
//update l2
List<String> results = new ArrayList<String>();
for(String s1 : l1){
for(String s2 : l2){
if(s2.contains(s1)){
results.add(s2);
}
}
//print the results
for(String r : results){
System.out.println(r);
}
Please check the following solution.请检查以下解决方案。 If you have any question, please ask.
如果您有任何问题,请提问。
import java.util.ArrayList;
import java.util.Arrays;
import java.util.List;
public class Test {
public static void main(String[] args) {
List<String> extractedvalue =Arrays.asList
("IT Infrastructure",
"Teams",
"Wave Analytics Starter Kit",
"Blog Post",
"Case Studies",
"InfoGraphics",
"Grazitti Site Development-Revamp");
List<String> hoursplusprojects =Arrays.asList
("Wave Analytics Starter Kit56:00:00",
"IT Infrastructure01:00:00",
"Teams08:00:00",
"Blog Post21:30:00",
"Case Studies02:30:00",
"InfoGraphics02:45:00",
"Grazitti Site Development-Revamp11:00:00",
"Content Marketing03:00:00",
"Off-Page Content04:30:00",
"SMM05:00:00",
"Guest Blog01:30:00",
"LiNC 1600:30:00",
"Alteryx Inspire Conference 201625:30:00",
"PPC02:00:00",
"Training13:45:00");
List<String> output=new ArrayList<String>();
for (String extractedvalueItem : extractedvalue) {
for(String hoursplusprojectItem : hoursplusprojects){
if(hoursplusprojectItem.startsWith(extractedvalueItem)){
output.add(hoursplusprojectItem);
}
}
}
System.out.println("EXTRACTEDVALUE:");
print(extractedvalue);
System.out.println("HOURSPLUSPROJECTS:");
print(hoursplusprojects);
System.out.println("OUTPUT");
print(output);
}
private static void print(List<String> list){
for (String item : list) {
System.out.println(item);
}
System.out.println();
}
}
Here's a correct answer with some sample code:这是一些示例代码的正确答案:
import java.util.ArrayList;
import java.util.HashMap;
import java.util.Iterator;
import java.util.List;
import java.util.Map;
import java.util.Map.Entry;
public class Test {
public static void main(String ...args){
List<String> a = new ArrayList<String>();
a.add("abc");
a.add("def");
a.add("ghi");
a.add("jkl");
List<String> b = new ArrayList<String>();
b.add("abc 123");
b.add("def 456");
b.add("ghi 789");
b.add("xyz 111");
Map<String, String> map = new HashMap<String, String>();
for (String item: b){
map.put(strip(item), item);
}
Iterator<Map.Entry<String, String>> iter = map.entrySet().iterator();
while (iter.hasNext()){
Entry<String, String> entry = iter.next();
if (!a.contains(entry.getKey())){
iter.remove();
}
}
System.out.println(map.values());
}
private static String strip(String input){
return input.split(" ")[0];
}
}
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