[英]How to solve java.security.AccessControlException
I need suggestions concerning the java.security.AccessControlException
, I get when executing the following code. 我需要有关
java.security.AccessControlException
建议,我在执行以下代码时会得到建议。 (I have consulted similar questions here but didn't success to make it work) (我在这里曾咨询过类似的问题,但未能成功实现)
Here is my server code: 这是我的服务器代码:
public class GetPageInfos extends UnicastRemoteObject implements RemoteGetInfo{
private static final String url="http://www.lemonde.fr/";
public class GetPageInfos extends UnicastRemoteObject implements RemoteGetInfo{
private static final String url="http://www.lemonde.fr/";
public GetPageInfos() throws RemoteException{
}
public String getSiteInfos() throws RemoteException {
Document doc;
try {
doc = Jsoup.connect(url).get();
String title = doc.title();
return "title is "+title;
} catch (IOException e) {
System.out.println("Faild! "+e.getMessage());
return "not found";
}
}
public static void main(String[] args){
try {
GetPageInfos infos= new GetPageInfos();
//System.setProperty("java.rmi.server.hostname","5lq04x1.gemalto.com");
Naming.rebind("RemoteGetInfo", infos);
/*GetPageInfos obj=new GetPageInfos();
RemoteGetInfo stub = (RemoteGetInfo) UnicastRemoteObject.exportObject(obj, 0);
Registry registry = LocateRegistry.getRegistry();
registry.bind("RemoteGetInfo", stub);
*/
System.out.println("server ready");
} catch (RemoteException e) {
System.out.println("GetPageInfos "+e.getMessage());
}
catch (MalformedURLException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
}
}
And here is my client code: 这是我的客户代码:
//RMI Client
public class PrintSiteInfos {
public static void main(String arg[])
{
System.setSecurityManager(new RMISecurityManager());
try
{
/*String host=null;
Registry registry = LocateRegistry.getRegistry(host);
RemoteGetInfo stub = (RemoteGetInfo) registry.lookup("RemoteGetInfo");
String response = stub.getSiteInfos();
System.out.println(response); */
RemoteGetInfo obj = (RemoteGetInfo) Naming.lookup( "RemoteGetInfo");
System.out.println(obj.getSiteInfos());
}
catch (Exception e)
{
System.out.println("PrintSiteInfos exception: " + e.getMessage());
e.printStackTrace();
}
}
}
So I got 所以我得到了
exception: access denied ("java.net.SocketPermission" "127.0.0.1:1099" "connect,resolve")
I found that I have to pass a policy file which I have like: 我发现我必须传递一个我喜欢的策略文件:
grant {
permission java.security.AllPermission;};
But how? 但是如何? Anyother suggestions?
还有其他建议吗?
You may grant only the socket permission not all permissions (which might be a security risk). 您可以只授予套接字权限,而不能授予所有权限(这可能会带来安全风险)。 Thus something like:
因此类似:
grant {
permission java.net.SocketPermission "127.0.0.1:1099", "connect, resolve";
};
Two ways to do it: 有两种方法:
1) As an argument at the command line 1)作为命令行的参数
java -Djava.security.policy=mypolicyfile PrintSiteInfo
2) within the JRE environment: 2)在JRE环境中:
Add the permission in the JRE_HOME/lib/security/java.policy file 在JRE_HOME / lib / security / java.policy文件中添加权限
Get rid of the security manager. 摆脱安全管理器。 You don't need it unless you're using the RMI codebase feature.
除非您正在使用RMI代码库功能,否则不需要它。
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