[英]PHP/MySQL get max date in a clause WHERE/AND
I'm trying this in my web application: 我正在我的Web应用程序中尝试此操作:
$data = date("Y-m-d", strtotime("-15 days", strtotime(date("Y-m-d"))));
$sql = "SELECT DISTINCT(Cliente.idCliente), Cliente.nomeCliente, Cliente.email, Cliente.cpf
FROM Cliente, Pontuacao
WHERE Cliente.idCliente = Pontuacao.idCliente
AND DATE_FORMAT(MAX(Pontuacao.timestampPontuacao), '%Y-%m-%d')='".$data."'
AND Cliente.receberMensagens=1
AND Cliente.numEstabelecimento='".$reg['numEstabelecimento']."'";
I tested the query directly in phpMyAdmin, like that: 我直接在phpMyAdmin中测试了查询,如下所示:
SELECT DISTINCT(Cliente.idCliente), Cliente.nomeCliente, Cliente.email, Cliente.cpf
FROM Cliente, Pontuacao
WHERE Cliente.idCliente = Pontuacao.idCliente
AND DATE_FORMAT(MAX(Pontuacao.timestampPontuacao), '%Y-%m-%d')='2016-03-28'
AND Cliente.receberMensagens=1
AND Cliente.numEstabelecimento=2
However, I'm getting the following error: 但是,出现以下错误:
#1111 - Invalid use of group function
#1111-无效使用组功能
I know this is happening because the line 我知道这是因为行
AND DATE_FORMAT(MAX(Pontuacao.timestampPontuacao), '%Y-%m-%d')='2016-03-28'
but I don't know how to fix that. 但我不知道该如何解决。 How can I fix that?
我该如何解决?
SELECT Cliente.idCliente, Cliente.nomeCliente, Cliente.email, Cliente.cpf
FROM Cliente
JOIN Pontuacao ON Cliente.idCliente = Pontuacao.idCliente
WHERE Cliente.receberMensagens=1
AND Cliente.numEstabelecimento=2
GROUP BY Cliente.idCliente, Cliente.nomeCliente, Cliente.email, Cliente.cpf
HAVING DATE_FORMAT(MAX(timestampPontuacao)), '%Y-%m-%d') = '2016-03-28'
It looks like you could make use of HAVING
. 看来您可以利用
HAVING
。
SELECT
DISTINCT(Cliente.idCliente),
Cliente.nomeCliente,
Cliente.email,
Cliente.cpf,
DATE_FORMAT(MAX(Pontuacao.timestampPontuacao), '%Y-%m-%d') AS max_date
FROM Cliente, Pontuacao
WHERE
Cliente.idCliente = Pontuacao.idCliente
AND Cliente.receberMensagens=1
AND Cliente.numEstabelecimento=2
HAVING
max_date = '2016-03-28';
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