[英]drop down menu from database
I am want to make a navigation menu with a sub menu on hover. 我想在悬停上创建一个带有子菜单的导航菜单。 I want to get this data from my database (to make it dynamic if data in database changes menu bar changes). 我想从数据库中获取此数据(如果数据库更改菜单栏中的数据更改,则使其动态化)。 In my database I have a table with the the following fields: 在我的数据库中,我有一个包含以下字段的表:
ID
, Name
, Level
, Parent_id
. ID
, Name
, Level
, Parent_id
。 Level
can be 0
or 1
. Level
可以为0
或1
。 0
for main menu 1
for sub menu the id
of a main menu is tied to the parent_id
field. 主菜单为0
,子菜单为1
,主菜单的id
绑定到parent_id
字段。
So for instance: 因此,例如:
ID Name Level Parent_id
1 Test 0
2 Test2 0
3 Test_sub 1 1
4 Test_sub2 2 2
I have managed to get the main menu items from the db but now I am a little bit stuck. 我设法从数据库中获取了主菜单项,但是现在我有点卡住了。 This is my code any help would be appriciated. 这是我的代码,将提供任何帮助。
<?php
$q2= "SELECT * from menu where level = 0 ";
$q2result = $db->query($q2);
while($a2 = $q2result->fetch(PDO::FETCH_ASSOC)){
echo "
<ul>
<li><a href='#' ><span> " . $a2['name'] . " </span></a>
<ul>
<li><a href='#' ><span> test </span></a></li>
</ul>
</ul>
";
}
?>
First load all your datas into variables. 首先将所有数据加载到变量中。 Never print/echo while in SQL statement. 在SQL语句中切勿打印/回显。
<?php
$q2= "SELECT * FROM menu ORDER BY Level ASC";
$q2result = $db->query($q2);
$nodes=array();
while($a2 = $q2result->fetch(PDO::FETCH_ASSOC)){
// assuming one parent node has already been assigned, due do level order into the SQL
if($node['Level']>0 && isset($nodes[$a2['id']])) {
$nodes[$a2['id']]['nodes'][]=$a2;
} else {
// parent node
$nodes[$a2['id']]=$a2;
$nodes[$a2['id']]['nodes']=array();
}
}
print "<ul>";
foreach($nodes as $node) {
print "<li>";
print "<a href='#'>".$node['Name']."</a>";
if(sizeof($node['nodes'])>0) {
print "<ul>";
foreach($node['nodes'] as $subnode) {
print "<li><a href='#'>".$subnode['Name']."</a></li>";
}
print "</ul>";
}
print "</li>";
}
print "</ul>";
?>
This may be much more improved, but with this, you can do what you ask, and improve it. 这可能会大大改善,但是有了它,您可以按自己的要求进行改进。
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