Oracle SQL中单行中的常见多行

Question

I have below query where instead of creating multiple entries(rows) for the same BN it should create entry in same row with FC,FM,MS value.

select bspt.BN, FC, FM, MS from(select distinct(ozt.BRD_ID),
bp.NAME as BN, 
os.OSS FC, '' FM, '' MS
from PR_BP ozt, PR_BP_BPP bp, BDD b, OS_VIEW os 
where bp.BRD_ID = ozt.BRD_ID AND ozt.BRD_ID = os.OBJECT_ID and 
os.OST = 'PR_BP_BPP' AND (ozt.BID = 10001)
and ozt.BID = b.BID AND ozt.BP_ACTIVE = 'Y'
UNION ALL
select distinct(ozt.BRD_ID),
bp.NAME as BN, 
'' FC, os.OST FM, '' MS
from PR_BP ozt, PR_BP_BPP bp, BRAND b, OS_VIEW os 
where bp.BRD_ID = ozt.BRD_ID AND ozt.BRD_ID = os.OBJECT_ID and 
os.OST = 'PR_BP_BPP' AND (ozt.BID = 10002)
and ozt.BID = b.BID AND ozt.BP_ACTIVE = 'Y'

And the above query is generating output with multiple entries for BNAME column. So instead of creating separate entry,it should create only single row for common BNAME.

Answer 1

All of this can be done with one query with conditional aggregation.

select bp.NAME as BIZNAME, 
max(case when bbp.BRAND_ID = 10001 then os.OBJECT_STATUS end) FC,
max(case when bbp.BRAND_ID = 10002 then os.OBJECT_STATUS end) FM, 
max(case when bbp.BRAND_ID = 10007 then os.OBJECT_STATUS end) MS 
from PR_BP bbp
JOIN PR_BP_BPP bp ON bp.BP_ID = bbp.BP_ID
JOIN BRAND b ON bbp.BRAND_ID = b.BRAND_ID
JOIN OS_VIEW os ON bbp.BP_ID = os.OBJECT_ID
where os.OBJECT_TYPE = 'PR_BP_BPP' AND bbp.BP_ACTIVE = 'Y'
group by bp.NAME