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如何使用C#泛型返回派生类

[英]How to return derived class with C# generics

I am trying to generate some test data using NBuilder for automation for all the classes that extends a base class wherein each class will have different fields. 我正在尝试使用NBuilder为扩展基类的所有类自动化生成一些测试数据,其中每个类将具有不同的字段。

Here is my code: 这是我的代码:

public interface Interface
{
    T method<T>() where T : BaseClass;
}

public class DrivedClass: BaseClass,Interface
{
    public T method<T>() where T : BaseClass
    {
        var derviedObj = Builder<DrivedClass>.CreateNew().Build();

        return derviedObj;
    }
}

return derviedObj giving error cannot implicity convert derviedObj to T return derviedObj给出错误的return derviedObj不能将derviedObj隐式转换为T

I'm not really familiar with nbuilder, but it looks like you could try something like this: 我对nbuilder并不是很熟悉,但是看起来您可以尝试执行以下操作:

public class DrivedClass: BaseClass,Interface
{
    public T method<T>() where T : BaseClass
    {
        var derviedObj = Builder<T>.CreateNew().Build();

        return derviedObj;
    }
}

Or this, if that's what you're really after: 或者,如果这就是您真正想要的:

public class DrivedClass: BaseClass,Interface
{
    public T method<T>() where T : BaseClass
    {
        var derviedObj = Builder<DrivedClass>.CreateNew().Build();

        return derviedObj as T;
    }
}

Then you will get T , but there's really no chance of knowing that it will succeed. 然后,您将得到T ,但是实际上没有任何机会知道它会成功。 What happens when you add another implementation that doesn't inherit DrivedClass ? 当您添加另一个不继承DrivedClass实现时会发生什么?

public class MoreDrivedClass : BaseClass, FooInterface
{

}

Then this cast will fail: 然后此强制转换将失败:

var drivedClass = new DrivedClass();
var foo = drivedClass.method<MoreDrivedClass>();

Then you will not be able to cast DrivedClass to MoreDrivedClass . 这样,您将无法将DrivedClassMoreDrivedClass Foo will be null. Foo将为空。

The method can't return DerivedClass because there is no way to know if T is that class or some other one: 该方法无法返回DerivedClass因为无法知道T是该类还是其他某个类:

SomeOtherDerived v = (new DrivedClass()).method<SomeOtherDerived>(); 

It is not clear what you trying to achieve, possibly something like following sample: 目前尚不清楚您要实现的目标,可能类似于以下示例:

public interface Interface<T> where T : BaseClass
{
    T method();
}

public class DrivedClass: BaseClass,Interface<DerivedClass>
{
  public DerivedClass method()
  {
      DerivedClass derviedObj = Builder<DrivedClass>.CreateNew().Build();
      return derviedObj ;
  }
}

Try with Activator.CreateInstance. 尝试使用Activator.CreateInstance。

public class DrivedClass: BaseClass,Interface
{
  public T method<T>() where T : BaseClass
    {
      var derviedObj = Activator.CreateInstance(typeof(T));
      return (T)derviedObj ; 

    }
}


 DrivedClass drOb = new DrivedClass ();
 var v = drOb.method<desiredType_T>();

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