[英]Ruby on Rails - Increment by 1 from last object
I am building a user gallery application, where user can create albums and upload images to their album. 我正在构建一个用户图库应用程序,用户可以在其中创建相册并将图像上传到他们的相册。 I am using
nested forms
for images. 我正在为图像使用
nested forms
。
In my images
database, I have a column called sort_order
. 在我的
images
数据库中,我有一列称为sort_order
。 I want to use sort_order
to manage the sorting and showing user, for ex: he is seeing 3 of 12 images, where 3 is number of sort_order
and 12 is number of total images in that album. 我想使用
sort_order
来管理排序和显示用户,例如:他正在查看12张图片中的3张,其中3张是sort_order
数量,而12张是该相册中总图像的数量。
sort_order
is integer
and default: 0
. sort_order
是integer
, default: 0
。 What I looking for is to increase/ increment
number of sort_order
for each image based on previous sort_order
of last image in same album. 我寻找的是增加/
increment
的数量sort_order
根据以往的每个图像sort_order
在同一专辑最后的形象。
For ex: image 1 will have sort_order: 1
, image 2 will then have previous images sort_id +1
=> sort_order: 2
and so on. 例如: 图像1将具有
sort_order: 1
,然后图像2将具有先前的图像sort_id +1
=> sort_order: 2
,依此类推。
Here is the code I am using now: 这是我现在使用的代码:
after_create :previous_image
def previous_image
img = user.images.order("id ASC")
img.each do |image|
image.increment!(:sort_order, self.sort_order + 1)
end
end
This does the work but in wrong sort. 这可以完成工作,但排序错误。
id sort_order
10 3
11 2
12 1
instead of having, id: 10
sort_order: 1
, its getting 3
. 而不是
id: 10
sort_order: 1
,它得到3
。
This is the log: 这是日志:
SQL (0.5ms) UPDATE "images" SET "sort_order" = ?, "updated_at" = ? WHERE "images"."id" = ? [["sort_order", 1], ["id", 398]]
user Load (0.1ms) SELECT "users".* FROM "users" WHERE "users"."id" = ? LIMIT 1 [["id", 160]]
Slide Load (0.1ms) SELECT "images".* FROM "images" WHERE "images"."user_id" = ? ORDER BY id DESC [["user_id", 160]]
SQL (0.1ms) UPDATE "images" SET "sort_order" = ?, "updated_at" = ? WHERE "images"."id" = ? [["sort_order", 1], ["id", 399]]
SQL (0.1ms) UPDATE "images" SET "sort_order" = ?, "updated_at" = ? WHERE "images"."id" = ? [["sort_order", 2], ["id", 398]]
user Load (0.2ms) SELECT "users".* FROM "users" WHERE "users"."id" = ? LIMIT 1 [["id", 160]]
Slide Load (0.1ms) SELECT "images".* FROM "images" WHERE "images"."user_id" = ? ORDER BY id DESC [["user_id", 160]]
SQL (0.1ms) UPDATE "images" SET "sort_order" = ?, "updated_at" = ? WHERE "images"."id" = ? [["sort_order", 1], ["id", 400]]
SQL (0.1ms) UPDATE "images" SET "sort_order" = ?, "updated_at" = ? WHERE "images"."id" = ? [["sort_order", 2], ["id", 399]]
SQL (0.1ms) UPDATE "images" SET "sort_order" = ?, "updated_at" = ? WHERE "images"."id" = ? [["sort_order", 3], ["id", 398]]
It starts from bottom and not top. 它从底部开始,而不是顶部。 How can I fix it?
我该如何解决?
If there is another way to do it without having the sort_order
column, I am open to it. 如果还有另一种方法可以不用
sort_order
列,那么我可以接受。
After receiving the form data, add an index (starting from 1) to the images array. 收到表单数据后,向图像数组添加一个索引(从1开始)。
Considering this is your images array from the form: 考虑到这是来自表单的图像数组:
images = [{name: 'Image 1', data: 123}, {name: 'Image 2', data: 456}]
Use with_index(1)
to attach the sort order to every element: 使用
with_index(1)
将排序顺序附加到每个元素:
images.map.with_index(1).to_a
images.map.with_index(1).to_a
=> [[{:name=>"Image 1", :data=>123}, 1], [{:name=>"Image 2", :data=>456}, 2]]
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.