从Powershell调用my.exe

Question

I am calling an executable from powershell using:

  $MyApp = .\MyApp_2.3.64.exe
  #$MyApp = ".\MyApp_2.3.64.exe"
  #$MyApp = '.\MyApp_2.3.64.exe'      
  $Options = "transform data.csv -output out -verbose $user"

  $MyApp transform data.csv -output out -verbose $user
  $MyApp $Options

  # Works
  .\MyApp_2.3.64.exe transform data.csv -output out -verbose $user

Based on below answer it works with:

  & $MyApp transform data.csv -output out -verbose $user

But it fails when I do:

  $options = "transform data.csv -output out -verbose $user"
  # $options = 'transform data.csv -output out -verbose $user'
  & $MyApp $options

How do I pass options etc. to the executable in a parameter?

Answer 1

$exe =  ".\MyApp_2.3.64.exe"
& $exe transform data.csv -output out -verbose

Or .$exe

It didn't work before as you $variable will just print value of a variable and to "execute" a variable you need to prefix it with a special character (either & or . ). Now, with parameters you are doing the same again, you just pass a string variable which holds all of your parameters. You need to pass array of parameters, like:

$exe =  ".\MyApp_2.3.64.exe"
$params = ("transform", "data.csv", "-output", "out", "-verbose")
& $exe $params