[英]Retrofit2 How to get redirect url @HEAD(“/”)
I have a minified URL and I want to have the final URL 我有一个缩略URL,我想拥有最终URL
With Retrofit 1.9 I used to do this : 使用Retrofit 1.9我曾经这样做:
@HEAD("/XXXXXXXXX")
void fetchFinalUrl(Callback<String> cb);
public void getUrl() {
mMinifyService.fetchFinalUrl(new Callback<String>() {
@Override
public void success(String s, Response response) {
response.getUrl();
}
[...]
}
But now with Retrofit 2 .getUrl() not exist any ideas how to do this? 但是,现在与Retrofit 2 .getUrl()不存在任何想法如何执行此操作?
Thanks in advance. 提前致谢。
EDIT 编辑
Finally got it! 终于明白了!
public class ApiProvider<T> {
private Retrofit retrofit;
private static final String END_POINT_MINIFY = "XXXXXXX";
public ApiProvider() {
initAdapter();
}
public T getService(Class<T> service) {
return retrofit.create(service);
}
private void initAdapter() {
HttpLoggingInterceptor interceptor = new HttpLoggingInterceptor();
interceptor.setLevel(HttpLoggingInterceptor.Level.BODY);
OkHttpClient client = new OkHttpClient.Builder()
.addInterceptor(interceptor)
.followRedirects(false)
.build();
retrofit = new Retrofit.Builder()
.baseUrl(END_POINT_MINIFY)
.addConverterFactory(new ToStringConverterFactory())
.client(client)
.build();
}
}
public interface IMinifyService {
@HEAD("/XXXXXXXXX")
Call<Void> fetchFinalUrl(Callback<String> cb);
}
public class MinifyServiceImpl {
private ApiProvider<IMinifyService> mApiProvider = new ApiProvider<>();
private IMinifyService mMinifyService = mApiProvider.getService(IMinifyService.class);
public Promiser<String, Integer> fetchMinifyUrl() {
return new Promiser<>((resolve, reject) -> mMinifyService.fetchMinifyUrl().enqueue(new Callback<Void>() {
@Override
public void onResponse(Call<Void> call, Response<Void> response) {
if (response.code() >= 300 && response.code() < 400){
resole.run(response.headers().get("Location"));
} else {
reject.run(response.code());
}
}
@Override
public void onFailure(Call<Void> call, Throwable t) {
reject.run(t.hashCode());
}
}));
}
}
if you want to use Promizer --> Click here 如果要使用Promizer-> 单击此处
response.raw().request().url()
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