[英]Is it possible to instantiate a function in php?
I am looking a PHP script example that contains the mysqli extension. 我正在寻找一个包含mysqli扩展的PHP脚本示例。 The code in question is as follows:
有问题的代码如下:
$conn = new mysqli("myServer", "myUser", "myPassword", "Northwind");
I'm confused as to wether this is a function or a class instance. 我很困惑这是一个函数或类实例。 If it is a function, is it possible to instantiate a function?
如果它是一个函数,是否可以实例化一个函数?
What confuses you is the constructor. 令你困惑的是构造函数。
This is a special public function inside a class which get's called straight after an instance gets created. 这是一个类中的特殊公共函数,它在创建实例后直接调用。
mysqli
in your case is a class, which has a constructor like this: 在你的情况下
mysqli
是一个类,它有一个像这样的构造函数:
public function __construct($server, $user, $password, $dbname) {
// do something
}
See: 看到:
http://php.net/manual/en/mysqli.construct.php http://php.net/manual/en/mysqli.construct.php
http://php.net/manual/en/language.oop5.decon.php http://php.net/manual/en/language.oop5.decon.php
Geekfact: Geekfact:
You can somehow get an "instance" of a function by using closures. 你可以通过使用闭包以某种方式获得函数的“实例”。 These arent real instances, just
callables
. 这些不是真实的例子,只是
callables
。
function createInstance() {
return function($a, $b) {
return $a + $b;
};
}
$myIndependendFunction = createInstance();
echo $myIndependendFunction(3, 2); // prints 5
You declare functions and use it , you declare objects (mysqli object in this case) and you instantiate it . 你声明函数并使用它 ,你声明对象 (在这种情况下是mysqli对象)并实例化它 。
You can read the manual. 你可以阅读手册。 http://www.php.net/manual/en/language.oop5.basic.php
http://www.php.net/manual/en/language.oop5.basic.php
If you want to contain your instantiation logic in one place you could wrap your current code within a function and return the ready to use mysqli class? 如果要在一个地方包含实例化逻辑,可以将当前代码包装在一个函数中并返回准备使用的mysqli类?
Example: 例:
<?php
function getMysqliConnection(){
return new mysqli("myServer", "myUser", "myPassword", "Northwind");
}
$conn = getMysqliConnection();
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