如何在单击超链接时运行php代码

Question

I am working on a module, "who viewed your profile" in a social networking site project. When a logged in user clicks on hyperlink of a user, he must be directed to a dummy page called view.Information of user who has clicked link of other user and username of user whose link has been clicked is stored in a database table, views. I tried doing this by calling a function updatetable on click of the hyperlink and using this function, I want to send variables viewername and viewedname to view.php, which inserts a record into views table.

 while($row=mysqli_fetch_array($res)) { ?> <a href="http://localhost/profileviews/view.php" onclick="updatetable('<?php echo $row['username']; ?>','<?php echo $username; ?>')"><?php echo $row['username']; ?></a> <?php } 

The above code displays links of all users and if a link is clicked, view.php page is opened where some php code has to be run. My updatetable function is as follows:

 <script type="text/javascript"> var viewedname,viewername; function updatetable(viewedname,viewername) { $.post('view.php' { viewer_name:viewername, viewed_name:viewedname } ); alert(viewedname); } </script> 

view.php code:

 if ($_POST && isset($_POST['viewer_name']) && isset($_POST['viewed_name'])) { $viewer_name = ($_POST['viewer_name']); $viewed_name = mysql_real_escape_string($_POST['viewed_name']); $con=new mysqli('localhost','root','','test'); if($con->connect_error) echo $con->connect_error; $r=mysqli_query($con,"insert into views(viewer,viewed) values('$viewer_name','$viewed_name')"); } 

Problems that I am facing: alert is not being shown and insertion is not happening after view.php code. Is there a mistake in the way I'm sending the viewer_name and viewed_name variables? I am new to php. Please help me out! Thank you :)

Answer 1

Missing a ( , ) in your javascript post:

Replace with:

$.post('view.php', { viewer_name:viewername, viewed_name:viewedname });

PHP:

Its better doing it this way:

if ($_POST){
  if(isset($_POST['viewer_name']) && isset($_POST['viewed_name'])) {
   //Do your stuff
  }
}