[英]Python IP address prefix matching
I am trying to match the following ranges of IP prefixes 10.[0-255], 192.168, 172.[16-31]
with the following regex statements: 我正在尝试将以下IP前缀范围10.[0-255], 192.168, 172.[16-31]
与以下正则表达式匹配:
if not ((re.match("^10\.([01][0-9][0-9]|2[0-4][0-9]|25[0-5])$", event["vpcprefix"]))
or (event["vpcprefix"] == "192.168")
or (re.match("^172\.(1[6-9]|2[0-9]|3[0-1])$", event["vpcprefix"]))):
#throw error, not matched
However, every time I try to run this against the test case 10.10
it throws an error. 但是,每次我尝试对测试用例10.10
运行此命令时,都会引发错误。 I'm not sure why, I can't find any errors in my statements. 我不确定为什么,在声明中找不到任何错误。
You have three patterns. 您有三种模式。 Clearly only the first has any chance of being true, and within that the closest option between the |
显然,只有第一个有可能为真,而在那个范围内|
之间的最接近选项 's is [01][0-9][0-9]
. 是[01][0-9][0-9]
。 But that's three digits, and 10
is two. 但这是三位数,而10
是两位。 Consider [01]?[0-9]?[0-9]
. 考虑[01]?[0-9]?[0-9]
。
How about: 怎么样:
if not ((event["vpcprefix"].split('.')[0] == '10')
or (event["vpcprefix"] == "192.168")
or (event["vpcprefix"].split('.')[0] == '172')):
#do stuff
don't think you really need the regex here. 不要以为这里真的需要正则表达式。
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