[英]linux - how to change directory and run a command on startup using rc.local
I am running ubunto on a box in ec2. 我在ec2的盒子上运行ubunto。 I would like to execute the following command in a specific directory each time the machine starts up: 每当计算机启动时,我想在特定目录中执行以下命令:
celery -A someapp.tasks --concurrency=1 --loglevel=info worker > output.log 2> errors.log
I've run 我跑了
sudo nano /etc/rc.local
and edited the file to read 并编辑文件以进行读取
#!/bin/sh -e
#
# rc.local
#
# This script is executed at the end of each multiuser runlevel.
# Make sure that the script will "exit 0" on success or any other
# value on error.
#
# In order to enable or disable this script just change the execution
# bits.
#
# By default this script does nothing.
(
cd /home/ubuntu/somefolder/
sh -e -c 'celery -A someapp.tasks worker -Ofair --loglevel=info > output.log > errors.log'
)
exit 0
But when the server starts up the command doesnt run. 但是,当服务器启动时,命令不会运行。 If I cd directly into /home/ubunto/somefolder and run the celery command the operation starts as expected. 如果我直接进入/ home / ubunto / somefolder,并运行celery命令,则操作将按预期启动。 How can I run this command each time the machine starts up? 机器每次启动时如何运行此命令?
Try it like this, using a subshell, so you don't change rc.local
's working dir: 像这样,使用子外壳程序,这样就不会更改rc.local
的工作目录:
(
cd /home/ubuntu/somefolder
celery -A someapp.tasks --concurrency=1 --loglevel=info worker >output.log 2> errors.log
)
exit 0
You can simply use the following: 您可以简单地使用以下内容:
sudo vi /etc/crontab
Add this at the end: 最后添加:
@reboot cd /home/ubuntu/somefolder/ && sh -e -c 'celery -A someapp.tasks worker -Ofair --loglevel=info > output.log > errors.log'
Cheers. 干杯。
我会尝试这个:
cd /home/ubuntu/somefolder && celery -A someapp.tasks --concurrency=1 --loglevel=info worker >output.log 2> errors.log
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