基于dict值作为键对列表进行排序

Question

I saw this method to sort list based on dict values as key.

Original Question here

Can we use this method to sort list of lists based on first value in each list?

trial_dict = {1:'ABC', 2:'PQR', 3:'DEF'}
trial_list = [['ABC','-','+','/','+','-','*'],
              ['DEF','-','+','/','+','-','*'],
              ['PQR','-','+','/','+','-','*']]

After sorting:

trial_list = [['ABC','-','+','/','+','-','*'],
              ['PQR','-','+','/','+','-','*'],
              ['DEF','-','+','/','+','-','*']]

Answer 1

You can use sorted() function.

trial_dict = {1:'ABC', 2:'PQR', 3:'DEF'}
trial_dict_inv = {v: k for k, v in trial_dict.items()}
trial_list = [['ABC','-','+','/','+','-','*'],
          ['DEF','-','+','/','+','-','*'],
          ['PQR','-','+','/','+','-','*']]


print sorted(trial_list, key= lambda z:trial_dict_inv[z[0]])

Output:

[['ABC', '-', '+', '/', '+', '-', '*'], ['PQR', '-', '+', '/', '+','-', '*'], ['DEF', '-', '+', '/', '+', '-', '*']]