一个可执行文件的“连续” C ++输出作为另一个程序的输入

Question

I am trying to pass the output generated by one executable as input into another. I have been able to send in one line at a time.

The problem is when I try to send in a 'sequence of lines generated in a while loop' from Program1 to be read as input by Program2. I tried piping the executables in terminal (as given below) , but it fails to work.

./Program1 | ./Program2  
./Program1 |xargs ./Program2  
./Program1 > ./Program2  

I want to avoid File I/O.

Note: Platform : Linux

==================

Something along the lines of the following example

Program1 (Writing to Terminal)

int main(int argc, char *argv[])
{
    int i = 2200;
    while(1){    
        printf("%d \n", i);
        i++;
    }
}

Program2 (Reading from Terminal, the output of Program1)

int main(int argc, char *argv[])
    {   
        while(1){ 
        // Read 'i' values
        cout << "There are " << argc << " arguments:" << endl;
        // Loop through each argument and print its number and value
        for (int nArg=0; nArg < argc; nArg++)
        cout << nArg << " " << argv[nArg] << endl;
        }

        return 0;
    }

Answer 1

The problem is that you are trying to read the program arguments . But when you pipe from one program to the next the output from the first program becomes the standard input ( std::cin ) of the second program.

Try this for program 2:

#include <string>
#include <iostream>

int main()
{
    std::string line;

    while(std::getline(std::cin, line)) // read from std::cin
    {
        // show that it arrived
        std::cout << "Line Received: " << line << '\n';
    }
}