在 PHP 中只比较没有年份的日期和月份，例如出生日期

Question

I want to compare current date's day and month with subscription date's day and month only. For example:

current date(d-m) = 3-6

And I want compare it with any other dm
How should I do it in PHP In my project condition is like birth date in which we don't compare year.

Answer 1

The trick in this is to let the month come first. This way PHP can compare the numbers by highest value. Take a look at the following example:

$aDate = DateTime::createFromFormat('m-d', '05-20');
$bDate = DateTime::createFromFormat('m-d', '06-29');

if ($aDate->format('md') > $bDate->format('md')) {
    echo "'aDate' is bigger than 'bDate'";
}

Answer 2

use like

$current_date = date("d-m");
$subscription = "03-06-2016";
$subscription_date  = date("d-m", strtotime($subscription));
if($current_date ==$subscription_date)
{
    echo "date is equal";
}else
{
    echo "date is not equal";
}

Answer 3

This may help you

$sdate = $row['subscription_date'];
$date1 = date("m-d");
$date2 = date("m-d",strtotime($sdate)) ;
if ($date1 == $date2) {

}

Answer 4

Use DATE_FORMAT() function to extract part of date:

Ref: http://dev.mysql.com/doc/refman/5.7/en/date-and-time-functions.html#function_date-format

SELECT * from table_name WHERE DATE_FORMAT(subscription_date, '%d-%m') = "05-05";

Answer 5

Use DateTime() PHP objects.

Considering you have an array with user info from mysql query result: ( $userData['suscriptionDate'] )

$today = new DateTime();

$userSuscription = new DateTime($userData['suscriptionDate']);

if ( $today->format('d') == $userSuscription->format('d') && $today->format('m') == $userSuscription->format('m')) {

    echo 'Congratulations!!';
}

Answer 6

I think, more elegant way to compare, especially when you have a full date with time is diff function of Datetime class:

$d1 = new Datetime();
$d2 = new Datetime('+3 months +2 days +3 hours');

$diff = $d1->diff($d2);
var_dump($diff->d); // 2
var_dump($diff->m); // 2
// or have a comparison as a string
var_dump($diff->format('Difference is in %R%a days'));
// output: Difference is in 63 days

Enjoy! Link to doc

Answer 7

If you only need to check if the jn date is the same as the current date, then you don't need to make more than one function call. Because you are not comparing greater than or less than, the format of your input is unimportant.

Code: ( Demo )

$subscription = '29-11';
var_export(date("j-n") === $subscription);
// at the moment, the result is true

• j is today's day of the month without any leading zeros and
• n is today's month without any leading zeros.