[英]In Scala, How to create TypeTag[Map[A,B]], while only TypeTag[A] and TypeTag[B] are available?
Assuming both type A and B are erased and unknown at run time. 假设类型A和类型B在运行时都被擦除并且未知。
Is there a way to construct TypeTag[Map[A,B]]? 有没有一种方法可以构造TypeTag [Map [A,B]]?
Preferrably using only explicit constructor, as in my real code both A and B are wildcard (it is possible to assign type parameters to 2 functions invoking them but why bother extracting 2 methods when they are only used once). 最好只使用显式构造函数,因为在我的真实代码中,A和B都是通配符(可以将类型参数分配给调用它们的2个函数,但是为什么只使用一次却要提取2个方法呢?
Thank you for your idea. 谢谢你的想法。 Any suggestion is appreciated.
任何建议表示赞赏。
Preferrably using only explicit constructor, as in my real code both A and B are wildcard
最好只使用显式构造函数,因为在我的真实代码中,A和B都是通配符
It isn't completely clear, but do you mean that you have tagA: TypeTag[_]
and tagB: TypeTag[_]
? 尚不完全清楚,但是您是说您拥有
tagA: TypeTag[_]
和tagB: TypeTag[_]
吗? If so, then you can do 如果是这样,那么你可以做
(tagA, tagB) match {
case (tagA: TypeTag[a], tagB: TypeTag[b]) =>
implicit val tagA1 = tagA
implicit val tagB1 = tagB
typeTag[Map[a, b]]
}
Somewhat ugly and boilerplaty, but I don't think there is a better way currently (and would be happy to learn otherwise). 有点丑陋和笨拙,但我认为目前还没有更好的方法(并且很乐意学习其他方法)。
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