在Windows上从tmpfile（）获取文件名

Question

How do I get the filename on Windows from by call to tmpfile() without using tmpnam() instead?

std::FILE* tmpf = std::tmpfile();   // Opens a temp file

Do it myself

const char *name = tmpnam(NULL);  // Get temp name
FILE *fp = fopen(name, "w");      // Create the file
// ...
fclose(fp);
remove(name);

Answer 1

One way is to convert from FILE to HANDLE

std::FILE* tmpf = std::tmpfile();
HANDLE handle = (HANDLE)_get_osfhandle(_fileno(tmpf));

Then use GetFinalPathNameByHandleW to obtain the file name (requires Vista or higher)

char buf[MAX_PATH];
GetFinalPathNameByHandleA(handle, buf, MAX_PATH, VOLUME_NAME_DOS);

Answer 2

Another way is to generate that filename by yourself - see post here:

https://stackoverflow.com/a/37736406/2338477

But please note also that tmpfile requires administrator privileges to work on some of windows - so using GetFinalPathNameByHandleW is acceptable only if your application is running with administrator priviledges.