Makefile：为什么命令替换不能在$（shell）函数中起作用？

Question

I have a variable in Makefile :

JAVABIN = $(shell dirname $(which java))

And when I echo the JAVA_HOME variable in Makefile , the variable definition complains:

dirname: missing operand
Try 'dirname --help' for more information.

When I quote the $(which java) , the JAVABIN is . , so the result is wrong. And I didn't understand how make reads a Makefile, maybe it is the cause. Thank you very much.

Answer 1

You need to escape the dollar:

JAVABIN = $(shell dirname $$(which java))

See 6.1 Basics of Variable References .

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The specific error message you received was caused by the fact that the $(which java) piece expanded to the empty string, since it was an undefined variable. Hence the dirname system command ended up seeing no arguments, in which case it complains of a "missing operand".