使用HTML的FOREACH中的FOREACH

Question

Right now I have this page where I use foreach to fill the page. I then have foreach inside of that to get another table with rows on the specific ID. The problem being anything under the nested foreach doesn't fill.

Table

Example:

<!-- Get The Person. Results in ONE person. -->
<?
$list = $db2->prepare(" SELECT * FROM Table WHERE ID = ? ");
$list->execute(array($id));
$data = $list->fetchAll();
foreach ($data as $row) :?>

<div><?=$row["name"]?></div>

<!-- Get The Colors. Gets as many results as there are for that ID. -->
<?
$list2 = $db2->prepare(" SELECT * FROM AnotherTable WHERE ID = ? ");
$list2->execute(array($id));
$data2 = $list2->fetchAll();
foreach ($data2 as $row2) :?>

<div><?=$row2["color"]?></div>

<?endforeach?>

<!-- Doesn't show up on the page. -->
<div><?=$row["food"]?></div>

<?endforeach?>

Answer 1

I think you are using the same $id on both tables which is what is causing the problem. If it is a child table and Table_ID is the foreign key, maybe

" SELECT * FROM AnotherTable WHERE Table_ID = ? "

or you could use join and do

"SELECT * FROM Table INNER JOIN AnotherTable ON Table.ID = AnotherTable.Table_ID WHERE ID = ? "

Am assuming Table_ID is your foreign key there.

Answer 2

As suggested in comment,

You should use JOIN in your query to avoid two foreach loop and get result in single query.

Write your query as below,

SELECT * FROM Table1 JOIN Table2 USING (ID) WHERE ID = ?;

same as

SELECT * FROM Table1 JOIN Table2 ON Table1.ID = Table2.ID WHERE Table1.ID = ?

Note:- To differentiate column names, you can use alias in column name.

Hope it will help you :-)