将最后一个元素移动到Flex容器中的下一行

Question

I have this structure in my HTML code:

<div style="display:flex">
    <div class="div_first">1</div>
    <div class="div_second">2</div>
    <div class="div_third">3</div>
    <div class="div_next_line">
      <div class="div_first">4</div>
      <div class="div_second">5</div>
      <div class="div_third">6</div>
    </div>
</div>

Is it possible to have 4 5 6 in second line with the same columns as 1 2 3, like so:

1    2    3
4    5    6

The structure of the HTML code cannot be changed.

Answer 1

Apply flex-wrap to the container.

Apply flex: 1 0 33% to the first three child divs.

To the fourth div apply flex-basis: 100%; display: flex flex-basis: 100%; display: flex .

To the children of the fourth div apply flex: 1 0 33% .

The idea is to force the fourth item to wrap, then have its children replicate the behavior of the children in the primary container.

Answer 2

Use flex-wrap for the parent and flex-basis for the children:

CSS:

.parent {
    flex-wrap: wrap;
    width: 400px;
    border: 2px solid blue;
}
.parent > .div_next_line {
    display: flex;
}
.parent > div {
    display: inline-block;
    flex-grow: 1;
    flex-basis: calc(100% / 3);
}
.parent > div > div {
    display: inline-block;
    flex-grow: 1;
    flex-basis: calc(100% / 3);
}

JSFiddle: https://jsfiddle.net/ghjbhjLu/1/

References:

CSS Tricks | Flex

Force n items, SO