[英]How to repeat same template in table-row using XSL-FO/Apache FOP
I'm trying to create a PDF from an XML file I've got and it's working fairly well so far using XSL-FO/Apache FOP. 我正在尝试从已有的XML文件创建PDF,到目前为止,使用XSL-FO / Apache FOP的效果都很好。
The XML file basically contains barcode information: the barcode itself and the barcode type (I'll add the barcode image at some point as well). XML文件基本上包含条形码信息:条形码本身和条形码类型(我还将在某些时候添加条形码图像)。
Now what I'd like to see as the output is this: 现在,我希望看到的输出是这样的:
-----------------------
| barcode1 | barcode2 |
| codetype1 | codetype2 |
-----------------------
| barcode3 | barcode4 |
| codetype3 | codetype4 |
-----------------------
And so on. 等等。
I've defined the following xsl: 我定义了以下xsl:
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.1" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:fo="http://www.w3.org/1999/XSL/Format" exclude-result-prefixes="fo">
<xsl:template match="barcode-list">
<fo:root xmlns:fo="http://www.w3.org/1999/XSL/Format">
<fo:layout-master-set>
<fo:simple-page-master master-name="simpleA4" page-height="29.7cm" page-width="21cm" margin-top="2cm" margin-bottom="2cm" margin-left="2cm" margin-right="2cm">
<fo:region-body/>
</fo:simple-page-master>
</fo:layout-master-set>
<fo:page-sequence master-reference="simpleA4">
<fo:flow flow-name="xsl-region-body">
<fo:block font-size="10pt">
<fo:table table-layout="fixed" width="100%" border-collapse="separate">
<fo:table-column column-width="45%"/>
<fo:table-column column-width="45%"/>
<fo:table-body>
<xsl:apply-templates select="item"/>
</fo:table-body>
</fo:table>
</fo:block>
</fo:flow>
</fo:page-sequence>
</fo:root>
</xsl:template>
<xsl:template match="item">
<fo:table-row>
<fo:table-cell>
<fo:block wrap-option="wrap">
<xsl:value-of select="name"/>
</fo:block>
<fo:block wrap-option="wrap">
<xsl:value-of select="format"/>
</fo:block>
</fo:table-cell>
</fo:table-row>
</xsl:template>
</xsl:stylesheet>
So there are two columns and I assumed I could just point it at the "item" template to fill in the cells. 所以有两列,我假设我可以将其指向“ item”模板来填写单元格。
Now I realize that the "item" template contains a <table-row>
tag and that that causes each item to appear in its own table row. 现在,我意识到“ item”模板包含一个
<table-row>
标记,该标记使每个项目都出现在其自己的表行中。 So what I get is this: 所以我得到的是:
-----------------------
| barcode1 | |
| codetype1 | |
-----------------------
| barcode2 | |
| codetype2 | |
-----------------------
| barcode3 | |
| codetype3 | |
-----------------------
| barcode4 | |
| codetype4 | |
-----------------------
My question is how to change the xsl to get the desired output rather than getting each item in its own table row? 我的问题是如何更改xsl以获取所需的输出,而不是使每个项目都位于其自己的表行中?
Omit the fo:table-row
and use the rarely-used starts-row
( https://www.w3.org/TR/xsl11/#starts-row ) and/or ends-row
( https://www.w3.org/TR/xsl11/#ends-row ) properties: 省略
fo:table-row
并使用很少使用的starts-row
( https://www.w3.org/TR/xsl11/#starts-row )和/或ends-row
( https://www.w3 .org / TR / xsl11 /#ends-row )属性:
<xsl:template match="item">
<fo:table-cell>
<xsl:if test="position() mod 2 = 1">
<xsl:attribute name="starts-row">true</xsl:attribute>
</xsl:if>
<fo:block wrap-option="wrap">
<xsl:value-of select="name"/>
</fo:block>
<fo:block wrap-option="wrap">
<xsl:value-of select="format"/>
</fo:block>
</fo:table-cell>
</xsl:template>
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.