[英]Uncaught exception 'PDOException' with message 'SQLSTATE[HY093]. I don't understand what's wrong
the backend part: 后端部分:
$producttitle = $_POST['product-title'];
$price = $_POST['price'];
$category = $_POST['Category'];
$file = $_FILE['file_upload'];
$description = $_POST['description'];
$adq = "INSERT INTO Advertenties (Titel, Prijs, Categorie, Image, Beschrijving) VALUES (:product-title, :price, :category, :file_upload, :description);";
$query = $GLOBALS['$odb']->prepare($adq);
$results = $query->execute(array(
":product-title" => $producttitle,
":price" => $price,
":category" => $category,
":file_upload" => $file,
":description" => $description
));
Front end: 前端:
<?php
require_once('../classes/layout_shared.php');
?>
<html lang="NL">
<head>
<meta charset="UTF-8">
<link rel="stylesheet" href="../css/bootstrap.css">
</head>
<body>
<div class="container">
<div class="col-md-9">
<form method="POST" action="../classes/upload.php" class="ad-form" enctype="multipart/form-data">
<lable>Titel</lable>
<input class="form-control" type="text" name="product-title"/>
<lable>Bedrag/Bieden vanaf:</lable>
<input class="form-control" type="text" name="price"/><br>
<lable>Categorie</lable>
<input class="form-control" type="" name="category"/><br>
<lable>Image</lable>
<input class="form-control" type="file" name="file_upload"/> <br>
<lable>Beschrijving:</lable>
<textarea class="form-control" placeholder="Voeg een beschrijving van het product toe" name="description"></textarea></br>
<input type="submit" name="toevoegen" value="Toevoegen"/>
</form>
</div>
</div>
</body>
</html>
So, this is my code above. 所以,这是我上面的代码。 It's for some reason giving me an error but I just can't undertand why.
由于某种原因给我一个错误,但我无法理解为什么。 I've scoured the internet, and all I can find is something doesn't match something.
我搜寻了互联网,发现的所有东西都不匹配。 I've gone through this so many times, its starting to annoy me now.
我经历了这么多次,现在开始惹恼我。
Any ideas? 有任何想法吗?
尝试用:product_title
替换:product-title
When in doubt, break your query into as many lines as possible so that you can sniper the issue rather than having MySQL always report an error on line 1: 如有疑问,请将查询分成尽可能多的行,以便您可以狙击问题,而不是让MySQL始终在第1行报告错误:
Turn 转
$adq = "INSERT INTO Advertenties (Titel, Prijs, Categorie, Image, Beschrijving) VALUES (:product-title, :price, :category, :file_upload, :description);";
Into 成
$adq = "INSERT INTO Advertenties
(Titel,
Prijs,
Categorie,
Image,
Beschrijving)
VALUES
(:product-title,
:price,
:category,
:file_upload,
:description);";
Also, is :product-title
a valid placeholder? 另外,
:product-title
是有效的占位符吗?
Beyond the sql placeholder name problem, you have multiple OTHER bugs: 除了sql占位符名称问题之外,您还有多个其他错误:
Field names are case sensitive: 字段名称区分大小写:
$category = $_POST['Category'];
^---
<input class="form-control" type="" name="category"/><br>
^----
$_FILES is an array of arrays: $ _FILES是一个数组数组:
$file = $_FILE['file_upload'];
":file_upload" => $file,
You can NOT bind array to a query placeholder. 您不能将数组绑定到查询占位符。 No idea what you're trying to do here - insert the actual file contents, or just the name of the file?
不知道您要在这里做什么-插入实际文件内容,还是仅输入文件名? Either way, it should be something like
无论哪种方式,它都应该像
":file_upload" => $file['tmp_name'],
to bind only one particular value out of the array. 只能将一个特定值绑定到数组之外。
instead of having the array as a parameter for the execute function you should bind all the values separately using bindValue. 而不是将数组作为execute函数的参数,您应该使用bindValue分别绑定所有值。 If you passed them as a parameter every value would be treated as a string, with bindValue you maintain the type of the variable.
如果将它们作为参数传递,则每个值都将被视为字符串,使用bindValue可以维护变量的类型。 The code would look something like this:
代码看起来像这样:
$adq = "INSERT INTO Advertenties (Titel, Prijs, Categorie, Image, Beschrijving) VALUES (:product-title, :price, :category, :file_upload, :description);";
$query = $GLOBALS['$odb']->prepare($adq);
$query->bindValue(":product-title", $producttitle);
$query->bindValue(":price", $price);
$query->bindValue(":category", $category);
$query->bindValue(":file_upload", $file);
$query->bindValue(":description", $description);
$result = $query->execute();
I hope that this helps. 我希望这个对你有用。
Succes gewenst 成功gewenst
looks like you have $category = $_POST[' Category ']; 看起来您有$ category = $ _POST [' Category ']; when you are sending 'category'.
当您发送“类别”时。 This is causing an undefined index.
这导致未定义的索引。 lowercase the c.
小写的c。 Along with Alex answer and you should be good
随着亚历克斯回答,你应该很好
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