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如何在链式下拉选项中使二元输入选择选项?

[英]How to make dimanic input select option in chained dropdown option?

It's my first time i ask a question here. 这是我第一次在这里问一个问题。 i'm stuck here, so i hope someone can solved this problem. 我被困在这里,所以我希望有人可以解决这个问题。 thanks :) 谢谢 :)

I have some php code that i want to made a input select option adding automaticallly when clicked a button in my form. 我有一些php代码,当我单击表单中的按钮时,我想使输入选择选项自动添加。 i mean, when the user clicked the button 3 times, so there are 3 input select options: 我的意思是,当用户单击按钮3次时,有3个输入选择选项:

示例从3选项中选择图像

it was working when i have using with this javascript code: 当我使用此javascript代码时,它正在工作:

var counter = 1;
var limit = 30;
function addInput(divName){
    var kdprov= $("#provinsi_id").val();
     if (counter == limit)  {
          alert("Maksimal input ialah " + counter + " sekolah");
     }
     else {
          var newdiv = document.createElement('div'); 
          newdiv.innerHTML = "<div><span class='input-group-addon' ><b> Sekolah ke-"+ (counter + 1)+"</span></b><select class='form-control' name='npsn"+ 
          (counter + 1)+"' ><option value='' disabled selected>--Pilih Sekolah--</option>'.<?php foreach($sekolah as $sekolah1){  ?>'<option value='<?php echo $sekolah1->npsn;?>' ><?php echo $sekolah1->nama_sekolah; ?></option><?php } ?>.'</select></select></div>";
          document.getElementById(divName).appendChild(newdiv);
          counter++;
     }
}

And this html code: 而这个html代码:

<input type="button" value="Tambah Sekolah" onClick="addInput('sekolah');"> </br></br>

but, the problem. 但是,问题。 they are retrieved all of variable $sekolah in database because i only used SELECT * FROM Sekolah in sql code. 他们在数据库中检索了变量$sekolah所有变量,因为我仅在sql代码中使用SELECT * FROM Sekolah

And now I want to made a query SELECT * FROM Sekolah where provinsi=$provinsi in my select option. 现在我要查询SELECT * FROM Sekolah where provinsi=$provinsi我的选择选项SELECT * FROM Sekolah where provinsi=$provinsi but, the other problem is variable $provinsi got from javascricpt value. 但是,另一个问题是从javascricpt值获得的变量$provinsi I mean,it is a chained dropdown. 我的意思是,这是一个链接的下拉列表。 when i choose a option from $provinsi , so i want #sekolah option will retrieve only from the selected $provinsi option. 当我从$provinsi选择一个选项时,因此我希望#sekolah选项将仅从所选的$provinsi选项中检索。

It worked in only static input, but i can't used it in my dimanic input select option. 它仅在静态输入中起作用,但是我无法在我的dimanic输入选择选项中使用它。

So, what should i do? 所以我该怎么做? I'm not really understand about javascript, so can someone give me the solution? 我对javascript不太了解,所以有人可以给我解决方案吗? i made it in codeIgniter. 我是在codeIgniter中取得的。

can i use a query in php code to get data from database in javascript? 我可以使用php代码中的查询从JavaScript中的数据库中获取数据吗?

Here is an example of how I would do this. 这是我将如何执行此操作的示例。 I would create the select menu on load, so there is always one available. 我会在加载时创建选择菜单,因此始终有一个可用菜单。 Then I would clone that select element whenever the button is clicked. 然后,只要单击按钮,我就会克隆该选择元素。 See the example below. 请参见下面的示例。

Working example: https://jsfiddle.net/tkfc031h/1 工作示例: https//jsfiddle.net/tkfc031h/1

HTML 的HTML

<div id="theSelectElements">
  <label class="foo">Number <span>1</span>
  <select>
    <option>one</option>
    <option>two</option>
    <option>three</option>
    <option>four</option>
    <option>five</option>
  </select>
  </label>
</div>

<button id="addOne">One more</button>

jQuery jQuery的

$('#addOne').click(function(){
  var theSelect = $('.foo:last-child').clone();
  var count = (parseInt(theSelect.find('span').text()) + 1);

  theSelect.find('span').html(count);
  theSelect.find('select').attr('name', "select"+count)

    $('#theSelectElements').append(theSelect);
})

First of all, let me clarify what you want. 首先,让我澄清一下您想要什么。

You have a dropdown "Provinsi" contains for example: 您有一个下拉列表“ Provinsi”,例如:

  • Aceh 亚齐
  • Sumatera Utara 苏门答腊
  • Riau & Kepri 廖内和凯普里

And you have a button "Tambah Sekolah". 然后您有一个按钮“ Tambah Sekolah”。

You select "Sumatera Utara" then click "Tambah Sekolah", you will have a new dropdown "Sekolah", contains for example: 选择“ Sumatera Utara”,然后单击“ Tambah Sekolah”,您将有一个新的下拉列表“ Sekolah”,例如:

  • sekolah sumut 1 塞科拉sumut 1
  • sekolah sumut 2 塞科拉sumut 2
  • sekolah sumut 3 塞科拉sumut 3

You select "Riau & Kepri" then click "Tambah Sekolah", you will have another new dropdown "Sekolah", contains for example: 选择“ Riau&Kepri”,然后单击“ Tambah Sekolah”,您将有另一个新的下拉列表“ Sekolah”,例如:

  • sekolah riau 1 塞科拉廖1
  • sekolah riau 2 塞科拉廖2
  • sekolah riau 3 塞科拉廖3

If the above requirements is what you want, then you should use ajax too. 如果上面的要求是您想要的,那么您也应该使用ajax。 Here what you need to do: 这里您需要做的是:

  1. Collect the value of selected "province" by using javascript 使用javascript收集所选“省”的值
  2. Send "province" by using ajax to a page in server-side 通过使用ajax将“省”发送到服务器端的页面
  3. A page in server-side, query the database for list of school filterd by "province" (SELECT * FROM sekolah WHERE provinsi = ?), then return the list of values to be shown in dropdown 服务器端的页面,在数据库中查询由“省”过滤的学校列表(SELECT * FROM sekolah WHERE provinsi =?),然后返回要在下拉列表中显示的值列表
  4. After ajax request has been completed, create a new dropdown with values from previous ajax response ajax请求完成后,使用先前ajax响应中的值创建一个新的下拉列表

In this example: https://jsfiddle.net/o0s1L4k1/ , see what happen if "Tambah Sekolah" button is clicked: 在此示例中: https ://jsfiddle.net/o0s1L4k1/,看看如果单击“ Tambah Sekolah”按钮会发生什么:

$.ajax({
    method: 'POST',
    url: 'list-sekolah.php', // page that will query schools by province
    data: {
        provinsi: $('#provinsi').val() // send currently selected province
    },
    success: function(response) {
        // build the new <select> and append it
        var html = $('<p>Sekolah: <select>' + response + '</select></p>');
        $('body').append(html);
    }
});

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