在PHP的rename（）函数中使用变量

Question

I'm trying to use variables in PHP's rename() function but I must be doing it wrong as it's not working.

$save = 'myfile-wf.png'; // this filename is actually created dynamically but I've just written it here for clarity. The variable is tested and working.

rename("/var/www/$save", "/var/www/html/wave/$save");

But it's not happening. Can you see what I'm doing wrong? Can I not use a variable in a filepath with rename()?

Answer 1

The rename() function expects strings as parameters for paths:

bool rename ( string $oldname , string $newname [, resource $context ] )

Strings don't have memory. Once you create one, PHP has no way to determine whether you created it using variables, reading data from a file or feeding it from a socket.

Most likely reasons include:

• Your strings do not contain what you think they do (as you've said, this is not actual code)

• rename() is throwing a warning but you haven't configured your PHP development box to display (all) errors on screen.