[英]Swift flatMap and generics
I'm trying to use flatMap to build a Resource<T>
in Swift, but keep getting a strange error, and only works when I force the cast. 我正在尝试使用flatMap在Swift中构建一个
Resource<T>
,但是一直遇到一个奇怪的错误,只有当我强制执行强制转换时才会有效。
Resource<T>
: Resource<T>
:
public struct Resource<T> {
let record: CKRecord
let parser: [String: AnyObject] -> T?
}
Working code: 工作代码:
public func buildResource<T>(resource: Resource<T>) -> T? {
var dataJson: [String: AnyObject] = [:]
dataJson["recordID"] = resource.record.recordID
for name in resource.record.attributeKeys {
dataJson[name] = resource.record[name]
}
return (dataJson as? [String: AnyObject]).flatMap(resource.parser)
}
The code above gives a warning that the casts always succeeds, which is true. 上面的代码给出了一个警告,表明强制转换总是成功,这是真的。 But when I try to remove the cast like so:
但当我尝试删除这样的演员时:
public func buildResource<T>(resource: Resource<T>) -> T? {
var dataJson: [String: AnyObject] = [:]
dataJson["recordID"] = resource.record.recordID
for name in resource.record.attributeKeys {
dataJson[name] = resource.record[name]
}
return dataJson.flatMap(resource.parser)
}
It gives the following error: 'flatMap' produces '[S.Generator.Element]', not the expected contextual result type 'T'?
它给出了以下错误:
'flatMap' produces '[S.Generator.Element]', not the expected contextual result type 'T'?
. 。
The parser is a struct init
like so: 解析器是一个
struct init
如下所示:
struct Example {
let name: String
let id: Int
}
extension Example {
init?(dataJson: [String: AnyObject]) {
guard let name = dataJson["name"] as? String else {
return nil
}
guard let id = dataJson["id"] as? Int else {
return nil
}
self.name = name
self.id = id
return
}
}
Any ideas how to fix this or a different approach? 任何想法如何解决这个或不同的方法? The idea here is to transform any CKRecord into a struct easily without needing to write a lot of boilerplate code.
这里的想法是将任何CKRecord转换为结构,而无需编写大量的样板代码。
Daniel Hall's answer is right but, by doing this, you'll be forced to change your parser
init signature to receive (String, AnyObject)
. Daniel Hall的答案是对的,但是,通过这样做,你将被迫改变你的
parser
初始签名以接收(String, AnyObject)
。
The best option would be to create another init
with this signature and parsing it to your json
signature's init
, still being able to create this struct from a raw json
. 最好的选择是使用此签名创建另一个
init
并将其解析为json
签名的init
,仍然能够从原始json
创建此结构。
extension Example {
init?(json: [String: AnyObject]) {
guard let name = json["name"] as? String else {
return nil
}
guard let id = json["id"] as? Int else {
return nil
}
self.name = name
self.id = id
return
}
init (tuple : (String, AnyObject)) {
var json : [String : AnyObject] = [:]
json["name"] = tuple.0
json["id"] = tuple.1
self.init(json: json)!
}
}
EDIT 编辑
As you're creating your dataJson
as a [String : AnyObject]
, you don't need to do a flatMap
on it, you can just return resource.parser(json: dataJson)
当您将
dataJson
创建为[String : AnyObject]
,您不需要对其执行flatMap
,您只需返回resource.parser(json: dataJson)
Looks like you have the wrong signature for your parser function. 您的解析器功能看起来有错误的签名。 The entire json dictionary is of type
[String : AnyObject]
, but the individual elements in that dictionary when enumerated with flatMap()
are of type (String, AnyObject)
, not [String : AnyObject]
. 整个json字典的类型为
[String : AnyObject]
,但使用flatMap()
枚举时该字典中的各个元素的类型为(String, AnyObject)
,而不是[String : AnyObject]
。
Try changing this: 尝试改变这个:
public struct Resource<T> {
let record: CKRecord
let parser: [String: AnyObject] -> T?
}
to this: 对此:
public struct Resource<T> {
let record: CKRecord
let parser: (String, AnyObject) -> T?
}
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